A continuation method for weakly Kannan maps
Abstract
The first continuation method for contractive maps in the setting of a metric space was given by Granas. Later, Frigon extended Granas theorem to the class of weakly contractive maps, and recently Agarwal and O’Regan have given the corresponding result for a certain type of quasicontractions which includes maps of Kannan type. In this note we introduce the concept of weakly Kannan maps and give a fixed point theorem, and then a continuation method, for this class of maps.
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Hindawi Publishing Corporation Fixed Point Theory and Applications Volume 2010, Article ID 321594, 12 pages doi:10.1155/2010/321594 Research Article A Continuation Method for Weakly Kannan Maps David Ariza-Ruiz and Antonio Jim´ enez-Melado Departamento de An´ alisis Matem´ atico, Facultad de Ciencias, Universidad de M´ alaga, 29071 M´ alaga, Spain Correspondence should be addressed to Antonio Jim´ enez-Melado, [email protected] Received 25 September 2009; Revised 4 December 2009; Accepted 6 December 2009 Academic Editor: Mohamed A. Khamsi Copyright q2010 D. Ariza-Ruiz and A. Jim´ enez-Melado. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. The first continuation method for contractive maps in the setting of a metric space was given by Granas. Later, Frigon extended Granas theorem to the class of weakly contractive maps, and recently Agarwal and O’Regan have given the corresponding result for a certain type of quasicontractions which includes maps of Kannan type. In this note we introduce the concept of weakly Kannan maps and give a fixed point theorem, and then a continuation method, for this class of maps. 1. Introduction Suppose that X, dis a metric space and that f:D⊂X→Xis a map. We say that f is contractive if there exists α∈0,1such that dfx,fy ≤αdx,yfor all x, y ∈D. The well-known Banach fixed point theorem states that fhas a fixed point if DXand X, dis complete. In 1962, Rakotch 1obtained an extension of Banach theorem replacing the constant αby a function of dx, y,ααdx, y, provided that αis nonincreasing and 0 ≤αt<1 for all t>0for a recent refinement of this result see 2. A similar generalization of the contractive condition was considered by Dugundji and Granas 3, who extended Banach theorem to the class of weakly contractive mappings i.e., ααx, y,with sup{αx, y:a≤dx,y≤b}<1 for all 0 <a≤b. Another focus of attention in Fixed Point Theory is to establish fixed point theorems for non-self mappings. In the setting of a Banach space, Gatica and Kirk 4proved that if f:U→Xis contractive, with Uan open neighborhood of the origin, then fhas a fixed point if it satisfies the well-known Leray-Schauder condition: fx/ λx, for x∈∂U, λ > 1.L-S Recently, Kirk 5has extended this result to the abstract setting of a certain class of metric spaces: the CAT0spaces. In the proof, the author uses a homotopy result due to
2 Fixed Point Theory and Applications Granas 6, which is known as continuation method for contractive maps. In fact, the jump from a Banach space setting to the metric space setting was given by Granas himself in 6 for more information on this topic see, for instance, 7–9. After Granas, Frigon 8gave a similar result for weakly contractive maps. A variant of the Banach contraction principle was given by Kannan 10, who proved that a map f:X→X, where X, dis a complete metric space, has a unique fixed point if f is what we call a Kannan map, that is, there exists α∈0,1such that, for all x, y ∈X, dfx,fy≤α 2dx,fxdy,fy.1.1 In this note, following the pattern of Dugundji and Granas 3, we extend Kannan theorem to the class of weakly Kannan maps i.e., ααx, y,withsup{αx, y:a≤dx, y≤ b}<1 for all 0 <a≤b.ThisisdoneinSection 2.InSection 3 we use a local version of the previous result to obtain a continuation method for weakly Kannan maps. 2. Weakly Kannan Maps In this section we follow the pattern of Dugundji and Granas 3to introduce the concept of weakly Kannan maps. Definition 2.1. Let X, dbe a metric space, D⊂X,andf:D→X. Therefore fis a weakly Kannan map if there exists α:D×D→0,1,withθa, b:sup{αx,y:a≤dx, y≤ b}<1 for every 0 <a≤bsuch that, for all x, y ∈D, dfx,fy≤αx, y 2dx,fxdy,fy.2.1 Remark 2.2. Clearly, any weakly Kannan map fhas at most one fixed point: if xfxand yfy, then dx,ydfx,fy≤1 2dx,fxdy,fy0.2.2 Remark 2.3. Notice that if f:D⊂X→Xis a weakly Kannan map and we define αfx, yon D×Das αfx,y⎧ ⎪ ⎨ ⎪ ⎩ 2dfx,fy dx,fxdy,fy if dx, fxdy,fy/ 0, 0 otherwise, 2.3 then αfis well defined, takes values in 0,1, satisfies sup{αfx, y:a≤dx, y≤b}<1 for all 0 <a≤bfor αfis smaller than any αassociated to f, and also satisfies 2.1,withα replaced by αf, for all x, y ∈D. Conversely, if αfis defined as in 2.3and satisfies the above set of conditions, then fis a weakly Kannan map, establishing in this way an equivalent definition for Kannan maps.
Fixed Point Theory and Applications 3 Remark 2.4. Although Kannan showed that the concept of Kannan map is independent of the concept of contractive map, Janos 11observed that any contractive map f:D⊂X→X whose Lipschitz constant defined by Lfsupdfx,fy dx,y:x,y ∈X, x / y2.4 is less than 1/3 is a Kannan map. Next, we exhibit an example of a weakly Kannan map f,withLf1/3, which is not a Kannan map, thus showing that the constant 1/3inthe aforementioned result by Janos is sharp. Example 2.5. Consider the metric space X0,∞with the usual metric dx, y|x−y|,and let f:X→Xbe the function defined as fx1/3log1ex. Then, Lf1/3andfis a weakly Kannan map, but not a Kannan map. The equality Lf1/3 follows from the fact that |fx|<1/3 for all x∈0,∞ together with lim x→∞ dfx,f0 dx,01 3.2.5 We also have that fis not a Kannan map because lim x→∞ 2dfx,f0 dx,fxd0,f01.2.6 To check that fis a weakly Kannan map, consider the function α:X×X→0,∞ given by 2.3. This function is well defined and also takes values in 0,1since Lf1/3. Next, assume that 0 <a≤band let us see that θa, bsup{αx, y:a≤dx,y≤b}<1. To see this, observe that |u−fu|→∞as u→∞, so there is M>0 such that |u−fu|>bfor all u>M. Observe also that fM, the restriction of fto 0,M, is a Kannan map with constant αM∈0,1, due to the fact that LfM<1/3, for fMis continuously differentiable on 0,M and |fu|<1/3 for all u∈0,M. We will see θa, b≤max{2/3,α M}.Todoit,suppose that x,y ∈0,∞with a≤|x−y|≤band 0 ≤x<y. Then, if y>M,use|y−fy|>band that Lf≤1/3toobtainαx,y≤2/3. Otherwise, we would have 0 ≤x<y≤Mand then αx,y≤αM. Although the way we have introduced the concept of weakly Kannan map has been by analogy with the work done by Dugundji and Granas in 3, we would like to mention that this extension may be done in some different ways. For instance, Pathak et al. 12, Theorem 3.1have proved the following result. Theorem A. Let X, dbe a complete metric space and suppose that f:X→Xis a map such that dfx,fy≤α1dx, fxdx, fxα2dy,fydy,fy,2.7 for all x,y ∈X,whereαi:R→0,1. If, in addition, there exists a sequence {xn}in Xwith dxn,fxn →0,thenfhas a fixed point in X.
4 Fixed Point Theory and Applications Observe that relation 2.7can be written in the following more general form: dfx,fy≤A1xdx, fxA2ydy,fy,2.8 for all x, y ∈X, where Ai:X→0,1,i1,2, and notice that any map satisfying 2.8also satisfies the relation 2.1with αx, y2 max{A1x,A 2y}. In fact, the arguments used by the authors in the proof of Theorem A are also valid for this class of maps. Next, we state this slightly more general result and include the proof for the sake of completeness. Then, we obtain, as a consequence, a fixed point theorem for weakly Kannan maps. Theorem 2.6. Let X, dbe a complete metric space and assume that A:X×X→0,∞is a bounded function satisfying the following condition: for any sequence {xn}in Xand u∈X, xn−→ u⇒lim sup Axn,u <1.∗ Assume also that f:X→Xis a map such that dfx,fy≤Ax, ydx,fxdy,fy,2.9 for all x,y ∈X. If there exists a sequence {xn}in Xwith dxn,fxn →0,thenfhas a unique fixed point uin X, and xn→u. Proof. Since Ais bounded, there exists M>0 such that |Ax, y|≤Mfor all x, y ∈X. Suppose that {xn}is a sequence in Xwith dxn,fxn →0anduse2.9to obtain that, for all n, m ∈N, dfxn,fxm≤Mdxn,fxndxm,fxm.2.10 This implies that {fxn}is a Cauchy sequence. Since X, dis complete, the sequence {fxn}is convergent, say to u∈X. Then xn→ubecause dxn,fxn →0. Thus, by ∗, lim sup Axn,u<1. That ufuis a consequence of the following relation and the fact that lim sup Axn,u<1, then du, fulim dfxn,fu≤lim sup Axn,u dxn,fxndu, fu du, fulim sup Axn,u . 2.11 Finally, uis the unique fixed point of fbecause if zfz: du, zdfu,fz≤Au, zdu, fudz, fz0.2.12 Corollary 2.7. Let X, dbe a complete metric space and suppose that f:X→Xis a weakly Kannan map. Then, fhas a unique fixed point u∈Xand, for any x0∈X, the sequence of iterates {fnx0}converges to u.
Fixed Point Theory and Applications 5 Proof. Since fis a weakly Kannan map, there exists a function α:X×X→0,1with θa, b:sup{αx, y:a≤dx,y≤b}<1 for all 0 <a≤b, satisfying 2.1for all x, y ∈X. Hence, the function A:X×X→0,1/2given as Ax, y1/2αx,yis bounded and satisfies the conditions ∗and 2.9. Consider any x0∈Xand define xnfxn−1,n1,2,.... We may assume that dx0,x 1>0 because otherwise we have finished. We will prove that dxn,fxn →0and hence, by Theorem 2.6,{xn}will converge to a point uwhich is the unique fixed point of f. First of all, observe that the inequality dxn1,x n≤αxn,x n−1dxn,x n−12.13 holds for all n≥1. In fact, it is a consequence of the following one, which is true by 2.1: dxn1,x n≤αxn,x n−1 2dxn1,x ndxn,x n−1.2.14 From 2.13we obtain that the sequence {dxn,x n−1}is nonincreasing, for 0 ≤ αxn,x n−1≤1, and then it is convergent to the real number dinf{dxn,x n−1:n1,2,... }.2.15 To prove that d0, suppose that d>0 and arrive to a contradiction as follows: use 0<d≤dxn,x n−1≤dx1,x 02.16 and the definition of θθd, dx1,x 0 to obtain αxn,x n−1≤θfor all n1,2,.... This, together with 2.13,givesthat d≤dxn1,x n≤θndx1,x 0,2.17 for all n1,2,..., which is impossible since d>0and0≤θ<1. Remark 2.8. We do not know whether Theorem A is, or not, a particular case of Theorem 2.6, although that is the case if the functions α1,α 2satisfy the additional assumption sup{α1t α2t:t≥0}<2. To see this, suppose that the map f:X→Xis in the conditions of Theorem A, that is, fsatisfies relation 2.7for some given functions αi:R→0,1,i1,2, and suppose also that the functions α1,α 2satisfy in addition sup{α1tα2t:t≥0}<2. Define A:X×X→0,∞as Ax,ymax{ax,ay}, where a:X→0,1is given by az1 2α1dz, fzα2dz, fz.2.18
6 Fixed Point Theory and Applications Let us see that, with this function A,fsatisfies the hypotheses of Theorem 2.6. Indeed, Ais clearly bounded and also satisfies ∗;if{xn}is a sequence in Xand u∈X,withxn→u, then sup{axn:n1,2,... }≤supα1tα2t 2:t≥0<1.2.19 Since we also have that au<1, we obtain that sup{Axn,u:n1,2,...}<1. Finally, to see that fsatisfies relation 2.9,userelation2.7with x, y ∈X, together with the same relation interchanging the roles of xand y, and the fact that dfx,fy dfy,fx,toobtainthat dfx,fy≤axdx, fxaydy,fy,2.20 from which the result follows. To prove the homotopy result of the next section, we will need the following local version of Corollary 2.7. Corollary 2.9. Assume that X, dis a complete metric space, x0∈X, r > 0, and f:Bx0,r→X is a weakly Kannan map with associated function αsatisfying 2.1.Ifθis defined as usual, and dx0,fx0<1 3minr 2,r1−θr 2,r,2.21 then fhas a fixed point. Proof. In view of Corollary 2.7,itsuffices to show that the closed ball Bx0,ris invariant under f. To prove it, consider any x∈Bx0,rand obtain the relation dx0,fx≤dx0,fx0dfx0,fx ≤dx0,fx0αx0,x 2dx0,fx0dx, fx ≤dx0,fx0αx0,x 2dx0,fx0dx, x0dx0,fx, 2.22 from which, having in mind that αx0,x≤1, dx0,fx≤3dx0,fx0αx0,xdx0,x.2.23 To end the proof, obtain that dx0,fx ≤rthrough the above inequality by considering two cases: if dx0,x≤r/2, then dx0,fx ≤rbecause dx0,fx0 ≤r/6. Otherwise, we would have r/2≤dx0,x≤r, and consequently αx0,x≤θr/2,r,from
Fixed Point Theory and Applications 7 which dx0,fx≤r1−θr 2,rrθr 2,rr. 2.24 3. A Homotopy Result In 1974 ´ Ciri´ c13introduced the concept of quasicontractions and proved the following fixed point theorem: suppose that X, dis a complete metric space and that f:X→Xis a quasicontraction, that is, there exists q∈0,1such that, for all x,y ∈X, dfx,fy≤qmaxdx, y,dx,fx,dy,fy,dx, fy,dy,fx.3.1 Then, fhas a fixed point in X. Observe that any contractive map, as well as any Kannan map, is a quasicontraction; thus, the theorem by ´ Ciri´ c generalizes the well known fixed point theorems by Banach and Kannan. On the other hand, Agarwal and O’Regan 14considered a certain class of quasicontractions: those maps f:X→X, where X, dis a metric space, for which there exists q∈0,1such that, for all x, y ∈X, dfx,fy ≤qmaxdx, y,dx, fx,dy,fy,1 2dx,fydy,fx, Q and gave the following homotopy result. Theorem B. Let X, dbe a complete metric space, Uan open subset of X, and H:U×0,1→X satisfying the following properties: iHx,λ/ xfor all x∈∂U and all λ∈0,1, iithere exists q∈0,1such that for all x, y ∈Uand λ∈0,1we have dHx,λ,Hy,λ ≤qmaxdx, y,dx, Hx,λ,dy,Hy,λ,1 2dx,Hy,λ,dy,Hx, λ, 3.2 iiiHx,λis continuous in λ, uniformly for x∈U. If H·,0has a fixed point in U,thenH·,λalso has a fixed point in Ufor all λ∈0,1. The above homotopy result includes the corresponding one for the class of Kannan maps, and in the following theorem we show that an analogous result is true for the wider class of weakly Kannan maps.
8 Fixed Point Theory and Applications Theorem 3.1. Let X, dbe a complete metric space, Uan open subset of X, and H:U×0,1→X satisfying the following properties: P1Hx,λ/ xfor all x∈∂U and all λ∈0,1, P2there exists α:U×U→0,1such that for all x, y ∈Uand λ∈0,1one has dHx,λ,Hy, λ≤αx,y 2dx,Hx, λ dy,Hy, λ,3.3 and θa, bsup{αx, y:a≤dx,y≤b}<1for all 0<a≤b, P3there exists a continuous function φ:0,1→Rsuch that, for every x∈Uand t, s ∈ 0,1,dHx,t,Hx, s ≤|φt−φs|. If H·,0has a fixed point in U,thenH·,λalso has a fixed point in Ufor all λ∈0,1. Proof. Consider the nonempty set A{λ∈0,1:Hx,λxfor some x∈U}.3.4 We will prove that A0,1, and for this it suffices to show that Ais both closed and open in 0,1. We start showing that Ais closed in 0,1: suppose that {λn}is a sequence in A converging to λ∈0,1and let us show that λ∈A. By definition of A, there exists a sequence {xn}in Uwith xnHxn,λ n. We will prove that {xn}converges to a point x0∈Uwith Hx0,λx0, thus showing that λ∈A. That {xn}is a Cauchy sequence is a consequence of the following relation, where we have used P2,P3, and the fact that xmHxm,λ m: dxn,x mdHxn,λ n,Hxm,λ m ≤dHxn,λ n,Hxn,λ m dHxn,λ m,Hxm,λ m ≤φλn−φλmαxn,x m 2dxn,Hxn,λ m dxm,Hxm,λ m φλn−φλmαxn,x m 2dHxn,λ n,Hxn,λ m ≤3 2φλn−φλm. 3.5
Fixed Point Theory and Applications 9 Write x0lim xnand let us see that x0∈Uand also that x0Hx0,λ.Thatx0Hx0,λis a consequence of the following relation: dx0,Hx0,λ ≤dx0,x ndxn,Hx0,λ ≤dx0,x ndHxn,λ n,Hxn,λ dHxn,λ ,Hx0,λ ≤dx0,x nφλn−φλ1 2dxn,Hxn,λ dx0,Hx0,λ ≤dx0,x n3 2φλn−φλ1 2dx0,Hx0,λ , 3.6 and that x0∈Uis straightforward from P1. Next we prove that Ais open in 0,1: suppose that λ0∈Aand let us show that λ0−δ, λ0δ∩0,1⊂A, for some δ>0. Since λ0∈A, there exists x0∈Uwith x0Hx0,λ 0. Consider r>0withBx0,r⊂Uand use the continuity of φto obtain δ>0 such that φλ−φλ0<minr 2,r1−θr 2,r,3.7 for all λ∈λ0−δ, λ0δ∩0,1. To show now that any λ∈λ0−δ, λ0δ∩0,1is also in A,itsuffices to prove that the map H·,λ:Bx0,r→Xhas a fixed point. And this is true by Corollary 2.9,since dx0,Hx0,λ dHx0,λ 0,Hx0,λ ≤φλ0−φλ <minr 2,r1−θr 2,r. 3.8 Remark 3.2. A careful reading of the proof shows that hypothesis P3in Theorem 3.1 can be easily replaced by the weaker hypothesis iiiin Theorem B. Remark 3.3. The counterpart to Theorem 3.1 for weakly contractive maps was proved by Frigon 8. In that result, it was assumed, in place of our 3.3, an equivalent formulation of the following condition H’: dHx,λ,Hy,λ≤αx,ydx,y.H’ Observe that condition H’means that all the maps H·,λ:U→X,λ∈0,1are weakly contractive, and with the same function α. Our condition 3.3is no surprise then. It also means that all the maps H·,λare of weakly Kannan type, and with the same function α. We end the section with an example of a homotopy Hsatisfying P1,P2,andP3 but not the hypotheses of Theorem B. In fact, the function fH·,1will be of weakly Kannan type, but will not satisfy the quasicontractivity condition Qhence, it will not be