Strong Convergence of Solutions and Attractors for Reaction-Diffusion Equations Governed by a Fractional Laplacian
Abstract
A nonlocal reaction-diffusion equation governed by a fractional Laplace operator on a bounded domain is studied in this paper. First, the strong convergence of solutions of the equations governed by fractional Laplacian to the solutions of the classical equations governed by a standard Laplace operator is proved, when the fractional parameter grows to 1. Second, for the autonomous case, the upper semicontinuity of global attractors with respect to the attractors of the limit problem is established. Apparently, these are the first results for this kind of problems on bounded domains.
Full text
S ong con e gence o solu ions and a ac o s o eac ion-di usion equa ions
go e ned by a ac ional Laplacian
Jiaohui Xu
Cen e o Nonlinea S udies, School o Ma hema ics,
No hwes Uni e si y, Xi’an 710127, P. R. China
Tom´
as Ca aballo1 2
Dp o. Ecuaciones Di e enciales y An´alisis Num´e ico,
Facul ad de Ma em´a icas, Uni e sidad de Se illa, c/ Ta ia s/n, 41012-Se illa, Spain
Depa men o Ma hema ics, Wenzhou Uni e si y,
Wenzhou, Zhejiang P o ince, 325035, P. R. China
Jos´e Vale o
Cen o de In es igaci´on Ope a i a, Uni e sidad Miguel He n´andez de Elche,
A enida de la Uni e sidad s/n, 03202-Elche, Spain
Abs ac
A nonlocal eac ion-di usion equa ion go e ned by a ac ional Laplace ope a o on a bounded
domain is s udied in his pape . Fi s , he s ong con e gence o solu ions o he equa ions go e ned
by ac ional Laplacian o he solu ions o he classical equa ions go e ned by a s anda d Laplace
ope a o is p o ed, when he ac ional pa ame e g ows o 1. Second, o he au onomous case,
he uppe semicon inui y o global a ac o s wi h espec o he a ac o s o he limi p oblem is
es ablished. Appa en ly, hese a e he i s esul s o his kind o p oblems on bounded domains.
Keywo ds: F ac ional Laplacian; S ong con e gence o solu ions; Global a ac o s.
AMS subjec classi ica ions. 35R11, 35A15, 35B41, 35K65
1. In oduc ion
In his pape , we s udy he p oblem
∂u
∂ + (−∆)γu= (u) + h( ),in O× (τ, ∞),
u= 0,on ∂O,
u(x, τ) = uτ(x),in O,
(1)
whe e (−∆)γ,γ∈(0,1), s ands o he ac ional Laplace ope a o ( ac ional Laplacian), Ois a
bounded subse o Rmwi h su icien ly smoo h bounda y, τ∈R,h∈L2
loc(R;L2(O)) and is a
con inuous unc ion sa is ying some app op ia e assump ions as speci ied la e .
Fi s o all, we need o decide which de ini ion o he ac ional Laplacian is mo e app op ia e o
ou analysis. I is well known ha , in he unbounded domain case, namely in Rm, he e a e se e al
equi alen de ini ions o ac ional Laplacian (see, o ins ance, [13] o en equi alen de ini ions),
bu in he bounded domain case, he e exis se e al de ini ions which a e no equi alen . We e e
he eade o he pape s [6, 16, 19] o mo e de ails. We will no discuss abou hem in his pape ,
bu will simply choose one o hose de ini ions o ou in es iga ion, mo e p ecisely he so called
“ egional”de ini ion (see [6]), in such a way ha we a e able o p o e he con e gence o solu ions
o (1) o he co esponding ones o he limi ing equa ion wi h s anda d Laplacian when γ→1−,
ensu ing his con e gence holds in he s ong sense, wha somehow jus i ies he sui abili y and
accu acy o he chosen de ini ion o ac ional Laplacian.
1Co esponding au ho
2E-mail add esses: [email protected] (J. Xu), [email p o ec ed] (T. Ca aballo), j [email p o ec ed] (J. Vale o).
1
2
The p ope ies o solu ions and a ac o s o p oblem (1) when γis ixed ha e been s udied
widely in he li e a u e. Fo example, he well-posedness and he exis ence o global a ac o s (in
bo h de e minis ic and andom se ing, wi h bounded o unbounded domains) o p oblem (1) ha e
been ex ensi ely in es iga ed in he li e a u e (see, e.g., [8, 17, 27, 28, 29, 30, 31] and he e e ences
he ein. Addi ionally, o a s ochas ic e sion o (1), he uppe semicon inui y o he a ac o s
was es ablished in [27, 28, 29] when a pa ame e in he noise e m a ies. I is ema kable ha
he de ini ion o ac ional Laplacian used in hese s ochas ic pape s is exac ly he “ egional”one
we will use in ou cu en analysis, wha ein o ces he idea ha he de ini ion we ha e chosen is
app op ia e.
Ou aim in his manusc ip is o analyze he beha io o solu ions o p oblem (1) when he
pa ame e γgoes o 1−, and he mo i a ion is based on he p ope ies o ac ional Laplace ope a o
(−∆)γas γ→1−, (see, o example, [8] and [21]). In [21, P oposi ion 4.4], he au ho s p o ed ha
(−∆)γu(x) con e ges o −∆u(x) as γ→1 o all x∈Rmwhen u∈C∞
0(Rm). In [8, P oposi ion
2.3], he au ho s p o ed ha , o e e y u∈C∞
0(Rm) and ∈W1,2
0(O), i holds
lim
γ→1−ZO
(−∆)γudx =−ZO
∆udx.
No ice ha in he pape s [3], [4] his ques ion was s udied o an abs ac pa abolic equa ion and
he Sch ¨odinge equa ion. Howe e , as a as we a e awa e, he e a e no esul s in he li e a u e
conce ning he con e gence o solu ions o (1) o he solu ions o he ollowing limi p oblem,
∂u
∂ −∆u= (u) + h( ),in O× (τ, ∞),
u= 0,on ∂O,
u(x, τ) = uτ(x),in O,
(2)
as he pa ame e γgoes o 1−. In [33], we comple ed a i s s ep by p o ing he con e gence o
solu ions wi h espec o he weak opology in L2(Rm) in he case ha he ex e nal unc ion is
sublinea . In his manusc ip , we will go much mo e u he o s udy he con e gence o solu ions
in he s ong opology sense o mo e gene al unc ions . Mo eo e , he uppe semicon inui y o
he global a ac o s will be es ablished as well.
The in e es in s udying p oblem (1) and i s s a iona y e sion comes om di e en ields as has
been desc ibed in ou pape [33] (see also [1, 2, 7, 9, 10, 11, 12, 18, 20, 23, 24, 25, 26, 32, 34, 35]
and he e e ences he ein).
This pape is o ganized as ollows. In Sec ion 2, we ecall he basic de ini ions and p ope ies
conce ning he ac ional Laplace ope a o s, es ablish he se ing o he p oblem we a e ackling
and impose he condi ions ha ensu e he exis ence and uniqueness o weak solu ions o p oblem
(1). In Sec ion 3, we imp o e i s he known esul s abou he con e gence o he ope a o (−∆)γ
by showing ha limγ→1−(−∆)γu=−∆us ongly in Lp((τ, τ +T)×Rm), o any p≥1 and
u∈C∞
0((τ, τ +T)×Rm), whe e τ∈R,T > 0. Also, limγ→1−(−∆)γu=−∆us ongly in
Lp(Rm), o any p≥1 and u∈C∞
0(Rm). A e ha , we p o e he main esul o he pape s a ing
ha he solu ions o p oblem (1) con e ge o he ones o he limi p oblem (2) in C([τ, τ +T]; L2(O)),
o any T > 0 as γ→1−. Finally, in Sec ion 4, we s udy he uppe semicon inui y o he global
a ac o s as he pa ame e γgoes o 1−in he au onomous si ua ion, ha is, when he unc ion h
belongs o L2(O).
3
2. Se ing o he p oblem
We conside he ollowing ac ional eac ion-di usion equa ion,
∂u
∂ + (−∆)γu= (u) + h( ),in O× (τ, ∞),
u= 0,on ∂O,
u(x, τ) = uτ(x),in O,
(3)
whe e (−∆)γ,γ∈(0,1), s ands o he ac ional Laplace ope a o , Ois a smoo h bounded subse
o Rm,τ∈Rand h∈L2
loc(R;L2(O)). Th oughou his pape , we assume ha ∈C(R) and he e
exis posi i e cons an s C ,κ,β1,β2and p≥2, such ha
( (s)− ( ))(s− )≤C (s− )2,∀s, ∈R,(4)
−κ−β1|s|p≤ (s)s≤κ−β2|s|p,∀s∈R.(5)
F om (5), we deduce ha he e exis s a cons an β3>0 such ha
| (s)| ≤ β3(|s|p−1+ 1),∀s∈R.(6)
We ix some µ∈(0, β2) and de ine he unc ion (u) = (u) + µu. Then, he equa ion in (3)
eads as ∂u
∂ + (−∆)γu+µu = (u) + h( ).(7)
I ollows om (5), (6) and he Young inequali y ha
(s)s≤κ−β2|s|p+µs2≤κ−β2|s|p,(8)
| (s)| ≤ β3(|s|p−1+ 1),(9)
o some posi i e cons an s κ, β2, β3.
Le Sdeno e he Schwa z space o apidly decaying C∞ unc ions on Rm. The ac ional Laplace
ope a o (−∆)γo u∈ S a poin x, o 0 < γ < 1, is de ined by,
(−∆)γu(x) = −1
2C(m, γ)ZRm
u(x+y) + u(x−y)−2u(x)
|y|m+2γdy, x ∈Rm,(10)
whe e C(m, γ) is he ollowing posi i e cons an
C(m, γ) = γ4γΓ(m+2γ
2)
πm
2Γ(1 −γ).(11)
I is well known [21] ha o any u∈ S, we ha e
(−∆)γu=F−1|ξ|2γFu,
whe e Fis he Fou ie ans o m gi en by
Fu=1
(2π)m/2ZRm
e−ix·ξu(x)dx,
and F−1is he in e se Fou ie ans o m. Fo 0 < γ < 1, we de ine he ac ional Sobole space
Wγ,2(Rm) := Hγ(Rm) by:
Hγ(Rm) = u∈L2(Rm) : ZRmZRm
|u(x)−u(y)|2
|x−y|m+2γdxdy < ∞,
endowed wi h he no m
kukHγ(Rm)=ZRm
|u(x)|2dx +ZRmZRm
|u(x)−u(y)|2
|x−y|m+2γdxdy1
2
.
4
In wha ollows, we deno e by k · kp he no m in Lp(Rm) o p > 2,whe eas by k · k and (·,·),
we deno e he no m and he inne p oduc o L2(Rm), espec i ely. By abusing o he no a ion,
(·,·) will be also used o he pai ing be ween Lq(Rm) and Lp(Rm). Mo eo e , we will conside he
Gaglia do semi-no m o Hγ(Rm),deno ed by k·k ˙
Hγ(Rm),which is gi en by,
kuk2˙
Hγ(Rm)=ZRmZRm
|u(x)−u(y)|2
|x−y|m+2γdxdy, u ∈Hγ(Rm).
The e o e, kuk2
Hγ(Rm)=kuk2+kuk2˙
Hγ(Rm) o all u∈Hγ(Rm). No ice ha Hγ(Rm) is a Hilbe
space wi h inne p oduc ,
(u, )Hγ(Rm)=ZRm
u(x) (x)dx +ZRmZRm
(u(x)−u(y))( (x)− (y))
|x−y|m+2γdxdy,
o u, ∈Hγ(Rm).Thanks o [21], he no m kukHγ(Rm)is equi alen o kuk2+k(−∆)γ
2uk21
2 o
u∈Hγ(Rm). Namely, i ollows ha
kuk2
Hγ(Rm)=kuk2+2
C(m, γ)k(−∆)γ
2uk2,∀u∈Hγ(Rm).
Since he ac ional Laplace ope a o (−∆)γgi en by (10) is nonlocal, we he e in e p e he homo-
geneous Di ichle bounda y p oblem (3) as ollows,
∂u
∂ + (−∆)γu= (u) + h( ),in O× (τ, ∞),
u= 0,on Rm O,
u(x, τ) = uτ(x),in O.
(12)
Na u ally, he limi p oblem (2) will be w i en as
∂u
∂ −∆u= (u) + h( ),in O× (τ, ∞),
u= 0,on Rm O,
u(x, τ) = uτ(x),in O,
(13)
so ha hey keep o mally consis en . Thus, we de ine he spaces
Vγ={u∈Hγ(Rm) : u= 0 a.e. on Rm O},
H={u∈L2(Rm) : u= 0 a.e. on Rm O},
V={u∈H1(Rm) : u= 0 a.e. on Rm O},
wi h hei dual spaces deno ed by V∗
γ,H∗and V∗, espec i ely. Mo eo e , we will use
kuk2
Vγ=kuk2+k(−∆)γ
2uk2,
o deno e he no m o space Vγ. The no m in Vwill be deno ed by k·kV.
Fu he mo e, le b:Vγ×Vγ→Rdeno e a bilinea o m gi en by,
bγ( 1, 2) = µ( 1, 2) + 1
2C(m, γ)ZRmZRm
( 1(x)− 1(y))( 2(x)− 2(y))
|x−y|m+2γdxdy, 1, 2∈Vγ,(14)
whe e C(m, γ) is he same as in (11). Fo con enience, we associa e wo ope a o s Aγ,Aγ:Vγ→V∗
γ
wi h b, such ha
< Aγ( 1), 2>(V∗
γ,Vγ)=µ( 1, 2)+ < Aγ( 1), 2>(V∗
γ,Vγ)=bγ( 1, 2),(15)
5
o all 1, 2∈Vγ,whe e <·,·>(V∗
γ,Vγ)is he duali y pai ing o V∗
γand Vγ. I is known [21] ha
he embeddings V⊂Vγ2⊂Vγ1a e con inuous o 0 < γ1≤γ2<1. Iden i ying Hwi h i s dual
space, we ob ain he chain o con inuous embeddings
V⊂Vγ⊂H⊂V∗
γ⊂V∗,∀γ∈(0,1) .
Pai ing be ween spaces Vand V∗will be deno ed by <·,·>(V∗,V ).
We conside wi hou loss o gene ali y ha h∈L2
loc(R;H) by se ing h( , x) = 0 o x∈Rm O.
De ini ion 1. Le τ∈R,uτ∈Hand γ∈(0,1). The unc ion u∈C([τ, ∞); H)is said o
be a weak solu ion o p oblem (12) i u(τ) = uτ,u∈L2
loc(τ, ∞;Vγ)∩Lp
loc(τ, ∞;Lp(Rm)),du
d ∈
L2
loc(τ, ∞;V∗
γ) + Lq
loc(τ, ∞;Lq(Rm)) and
d
d (u, ξ) + 1
2C(m, γ)ZRmZRm
(u( , x)−u( , y))(ξ(x)−ξ(y))
|x−y|m+2γdxdy
=ZO
( (u( , x)) + h( , x)) ξ(x)dx,
o any ξ∈Vγ∩Lp(Rm), in he sense o scala dis ibu ions in (τ, ∞).
In [27, Theo em 2.3], one can see ha p oblem (12) possesses a unique weak solu ion o any
uτ∈Hand γ∈(0,1). In addi ion, his solu ion is con inuous wi h espec o he ini ial da um uτ
in H, and sa is ies he ene gy equali y,
d
d kuk2+C(m, γ)kuk2˙
Hγ(Rm)= 2 ZO
( (u( , x)) + h( , x)) u( , x)dx, o a.a. ≥τ.
De ini ion 2. Le τ∈Rand uτ∈H. The unc ion u∈C([τ, ∞); H)is said o be a weak
solu ion o p oblem (13) i u(τ) = uτ,u∈L2
loc(τ, ∞;V)∩Lp
loc(τ, ∞;Lp(O)),du
d ∈L2
loc(τ, ∞;V∗) +
Lq
loc(τ, ∞;Lq(O)) and
d
d (u, ξ) + ZO
∇u·∇ξdx =ZO
( (u( , x)) + h( , x)) ξ(x)dx,
o any ξ∈V∩Lp(O), in he sense o scala dis ibu ions in (τ, ∞).
Recall ha (see, e.g., [5] o [22]) p oblem (2) possesses a unique weak solu ion o any uτ∈H,
which is con inuous wi h espec o he ini ial da um uτin H.
3. Con e gence o solu ions
Ou aim now is o p o e ha he solu ions o p oblem (12) con e ge, as γ→1−, o he unique
solu ion o he limi p oblem wi h γ= 1, ha is, o he unique solu ion o he s anda d eac ion-
di usion equa ion (13). I is well known [21, P oposi ion 4.4] ha i u∈C∞
0(Rm), hen
lim
γ→1−(−∆)γu(x) = −∆u(x), o all x∈Rm. (16)
Le C∞
0(X) be he space o in ini ely di e en iable unc ions u:X→Rwi h compac suppo ,
whe e Xis a Banach space. Deno e by D0 he space o dis ibu ions o D=C∞
0((τ, τ +T)×Rm)
and by <·,·>(D0,D) he duali y pai ing o D0and D. Deno e by BR he ball in Rmcen e ed a 0
wi h adius R.
Now, we ecall a esul p o ed in [33] which ex ends he con e gence esul (16) o a mo e gene al
one.
6
Lemma 3. (See [33, Lemma 3.1]) Fo any τ∈R,T > 0and u∈C∞
0((τ, τ +T)×Rm), he ollowing
s a emen holds,
lim
γ→1−(−∆)γu=−∆u, s ongly in Lp((τ, τ +T)×Rm),∀p≥1.
In pa icula , limγ→1−(−∆)γu=−∆uin he sense o dis ibu ions in D0.
Now, in a simila way we s a e he ollowing esul .
Lemma 4. (See [33, Lemma 3.2]) Fo any u∈C∞
0(Rm),limγ→1−(−∆)γu=−∆us ongly in
Lp(Rm) o any p≥1.
We also need he ollowing echnical lemma which is c ucial o ou analysis.
Lemma 5. (i) Fo any γ∈1
2,1and ∈Vγ, we ha e
k kV1
2
≤ 3
2k kV γ.(17)
(ii) The e exis s a posi i e cons an Ksuch ha , o any ∈Vγ,
Aγ
V∗≤Kk kV γ, o any γ∈(0,1) .(18)
P oo . (i) Since
1
2<1
2γ<1,0<1−1
2γ<1
2.
By he Fou ie ans o m and Young inequali y, he es ima e (17) ollows om
k k2
V1
2
=k k2+k(−∆)1
4 k2=ZRm
(1 + |ξ|)|F (ξ)|2dξ
≤ZRm2−1
2γ+1
2γ|ξ|2γ|F (ξ)|2dξ
≤3
2ZRm1 + |ξ|2γ|F (ξ)|2dξ =3
2k k2
Vγ.
(i) Fo he second s a emen , le us i s p o e he exis ence o posi i e cons an Ksuch ha
(−∆)γ
2u
≤KkukV,∀u∈V. (19)
On he one hand, by Fubini’s Theo em, we ha e
ZRmZ|x−y|<1
|u(x)−u(y)|2
|x−y|m+2γdxdy ≤ZRmZB1
|u(y+z)−u(y)|2
|z|2|z|m+2(γ−1) dzdy
≤ZRmZB1
1
|z|m+2(γ−1) Z1
0
|∇u(y+ z)|d 2
dzdy
≤ZB1
1
|z|m+2(γ−1) Z1
0ZRm
|∇u(y+ z)|2dyd dz
≤ kuk2
VZB1
1
|z|m+2(γ−1) dz
≤ kuk2
Vωm−1Z1
0
1
ρ2γ−1dρ =ωm−1
2 (1 −γ)kuk2
V.
7
On he o he hand, he change o a iable implies
ZRmZ|x−y|≥1
|u(x)−u(y)|2
|x−y|m+2γdxdy ≤4ZRmZ|x−y|≥1
|u(y)|2
|x−y|m+2γdxdy
= 4 kuk2Z|z|≥1
1
|z|m+2γdz
≤4kuk2ωm−1Z∞
1
1
ρ2γ+1 dρ
=2ωm−1
γkuk2
V.
Thus, combining he abo e wo es ima es, we ob ain
(−∆)γ
2u
2=C(m, γ)
2kuk2˙
Hγ(Rm)
=C(m, γ)
2ZRmZRm
|u(x)−u(y)|2
|x−y|m+2γdxdy
≤ωm−1C(m, γ)
4 (1 −γ)+C(m, γ)
γkuk2
V
≤K2kuk2
V,
o some cons an s K > 0, whe e he las inequali y ollows om he ac
lim
γ→0+
C(m, γ)
γ= lim
γ→0+
C(m, γ)
γ(1 −γ)=2
ωm−1
,
see [21, Co olla y 4.2] o mo e de ails. Immedia ely, by he Young inequali y and (19), we ind
Aγ
V∗= sup
u∈V, kukV≤1< Aγ( ), u >(V∗,V )
= sup
u∈V, kukV≤1< Aγ( ), u >(V∗
γ,Vγ)
= sup
u∈V, kukV≤1
1
2C(m, γ)ZRmZRm
( (x)− (y))(u(x)−u(y))
|x−y|m+2γdxdy
≤sup
u∈V, kukV≤1
1
2C(m, γ)k k˙
Hγ(Rm)kuk˙
Hγ(Rm)
= sup
u∈V, kukV≤1
(−∆)γ
2
(−∆)γ
2u
≤Ksup
u∈V, kukV≤1
(−∆)γ
2
kukV≤K
(−∆)γ
2
≤Kk kV γ.
We inish he p oo o his lemma.
We can now es ablish he main esul o his pape abou he con e gence o solu ions.
Theo em 6. Le un
τ→uτin H, le un(·)be he solu ion o p oblem (12) o γ=γnwi h ini ial
alue un
τ. Then un→uin C([τ, τ +T]; H)as n→ ∞ o any T > 0, whe e u(·)is he unique
solu ion o p oblem (13). I un
τ→uτweakly in H, hen un→uin C([τ+ε, τ +T]; H)as n→ ∞
o any 0< ε < T.
8
P oo . Conside a sequence γn→1−. Le un(·) be he unique solu ion o p oblem (12) wi h ini ial
alue un
τ. Mul iplying equa ion (7) by un, using he Young inequali y and on accoun o (8), we
de i e
1
2
d
d kunk2+µkunk2+1
2C(m, γn)kunk2˙
Hγn(Rm)
≤κ−β2kunkp
p+kh( )k kunk
≤κ−β2kunkp
p+1
2µkh( )k2+µ
2kunk2,(20)
which is equi alen o
d
d kunk2+µkunk2+C(m, γn)kunk2˙
Hγn(Rm)+ 2β2kunkp
p≤2κ+1
µkh( )k2.(21)
Mul iplying (21) by eµs and in eg a ing i o e he in e al (τ, ), we deduce
kun( )k2≤ kun
τk2e−µ( −τ)+2κ
µ1−e−µ( −τ)+1
µZ
τ
e−µ( −s)kh(s)k2ds. (22)
Then o T > 0, we in e ha
sup
∈[τ,τ+T]
kun( )k2≤MT,(23)
whe e MTdepends on T, and
Zτ+T
τC(m, γn)kun(s)k2˙
Hγn(Rm)+ 2β2kun(s)kp
pds ≤MT.(24)
The e o e, he sequence {un}is bounded in L∞(τ, τ +T;H)∩Lp(τ, τ +T;Lp(Rm)). By (23) and
(24), we ha e
Zτ+T
τ
(−∆)γn
2un(s)
2ds ≤Zτ+T
τ
C(m, γn)kun(s)k2˙
Hγn(Rm)ds ≤MT,(25)
Zτ+T
τ
kun(s)k2
Vγnds ≤MT+TMT.(26)
Hence, in iew o (26) and Lemma 5(i), he e exis s n0>0, such ha γn∈[1
2,1) o n≥n0. Then,
we ha e
Zτ+T
τ
kunk2
V1
2
ds ≤3
2MT+TMT,
which implies {un}is bounded in L2(τ, τ +T;V1
2). Also, (26) and (18) imply ha {Aγn(un)}is
bounded in L2(τ, τ +T;V∗). Mo eo e , by (24) and (9), we in e ha { (un)}is bounded in
Lq(τ, τ +T;Lq(Rm)). The e o e, {dun
d }is bounded in Lq(τ, τ +T;Lq(Rm))+L2(τ, τ +T;V∗). Then
he e exis unc ions u, χ, ξ such ha , up o a subsequence which we elabel he same, we deduce
he ollowing con e gences,
un→uweak-s a in L∞(τ, τ +T;H),(27)
un→uweakly in L2(τ, τ +T;V1
2),(28)
un→uweakly in Lp(τ, τ +T;Lp(Rm)),(29)
(un)→χweakly in Lq(τ, τ +T;Lq(Rm)),(30)
Aγn(un)→ξweakly in L2(τ, τ +T;V∗),(31)
dun
d →du
d weakly in Lq(τ, τ +T;Lq(Rm)) + L2(τ, τ +T;V∗).(32)
9
Since he embedding V1
2⊂His compac and he embedding H⊂(V∩Lp(Rm))∗is con inuous, a
s anda d Compac ness Theo em [22, Theo em 8.1] implies ha
un→us ongly in L2(τ, τ +T;H),(33)
un( , x)→u( , x) o a.a. ( , x)∈(τ, τ +T)× O.(34)
F om he con inui y o and [15, Lemma 1.3], we also ob ain ha χ= (u).
Fu he , we need o p o e ha ξ=−∆u. By Lemma 3, o a bi a y ϕ∈ D, we ha e
< Aγn(un), ϕ >(D0,D)=Zτ+T
τ
< Aγn(un), ϕ >(V∗,V )d
=Zτ+T
τ
< un, Aγn(un)>(V,V ∗)d =Zτ+T
τZRm
un(−∆)γnϕdxd
γn→1−
−→ Zτ+T
τZRm
u(−∆)ϕdxd =Zτ+T
τ
< u, −∆ϕ >(V,V ∗)d
=<−∆u, ϕ >(D0,D),
he abo e con e gence holds hanks o he ac s ha un→uin L2(τ, τ+T;H) and (−∆)γnϕ→ −∆ϕ
in L2(τ, τ +T;H). Consequen ly, Aγn(un)→ −∆uas γn→1−in he dis ibu ional sense, which
implies ha ξ=−∆u.
Thus, o any η∈L2(τ, τ +T;V)∩Lp(τ, τ +T;Lp(Rm)), he abo e con e gences yield ha
0 = Zτ+T
τ
<dun
d , η >(V∗+Lq(Rm),V ∩Lp(Rm)) d +Zτ+T
τ
< Aγn(un), η >(V∗,V )d
−Zτ+T
τZO
( (un) + h)ηdxd
−→ Zτ+T
τ
<du
d , η >(V∗+Lq(Rm),V ∩Lp(Rm)) d +Zτ+T
τ
<−∆u, η >(V∗,V )d
−Zτ+T
τZO
( (u) + h)ηdxd .
Mo eo e ,
u∈L∞(τ, τ +T;H)∩Lp(τ, τ +T;Lp(Rm)),
u∈L2(τ, τ +T;V1
2),
du
d ∈Lq(τ, τ +T;Lq(Rm)) + L2(τ, τ +T;V∗),
−∆u∈L2(τ, τ +T;V∗).
Since −∆u( )∈V∗, we de i e ha u( )∈V o a.a. ∈(τ, τ +T). Hence,
k∇u( )k2=<−∆u( ), u( )>(V∗,V )≤ k∆u( )kV∗k∇u( )k,
and, consequen ly,
u∈L2(τ, τ +T;V).
The e o e, u(·) is he weak solu ion o p oblem (13).
Since e e y con e ging sequence has he same limi , i ollows ha he con e gences (27)-(34)
hold o he whole sequence. Also, we deduce om (23) ha o n, 0∈[τ, τ +T] such ha n→ 0,
we ha e
un( n)→u( 0) weakly in H. (35)