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Exponential law for uniformly continous proper maps

Ayala Gómez, Rafael; Domínguez Murillo, Eladio; Quintero Toscano, Antonio Rafael

Abstract

The purpose of this note is to prove the exponential law for uniformly continuous proper maps.

Full text

Publicacions Ma emá iques, Vol 32 (1988), 123-127 . Abs ac EXPONENTIAL LAW FOR UNIFORMLY CONTINUOUS PROPER MAPS R . AYALA, E . DOMINGUEZ, A . QUINTERO The pu pose o his no e is o p o e he exponen ial law o uni o mly con inuous p ope maps . Le X be a egula space and Y a locally compac egula space . I is well known ha he spaces o con inuousmaps C(X x Y, Z) and C(X, C(Y Z)) a e homeomo phic conside ing he compac -open opology . This p ope y has impo an consequences in he s udy o he pa h-componen s o he unc ion spaces and in Homo opy Theo y : The exponen ial law o he uni o mly con- inuous p ope maps has simila consequences in some pa icula cases . All he spaces we conside , unless o he wise men ioned, a e me ic spaces . A p ope map will . b e a con inuous map : X -+ Y such ha o e e y compac subspace K o Y, -1(K) is á compac in X . To abb e ia e,- we will say ha is a p-map . A u-map is a uni o mly,cgn inuous map, and a up-map will be a uni o mly con inuous p-map . A up-isomo phism l a homeomo phism such ha and -1 a e u-maps ., By C(X, Y),  C p (X, Y) and C  p (X, Y) we will deno e he se s o con inuous maps, p-maps and up-maps be ween X and Y, espec i ely . Wi h Cú p (X, Y) we will ep esen he space o up-maps wi h he opology o uni o m con e gen e . In his no e we p o e ha he up-maps ollow he exponen ial law i X is compac ; ha is, he unc o s X x (-) and Cú p (X, -) a e adjoin . We also p o e ha i X is no compac hese unc o s a e no gene ally adjoin . A up-homo opy (p-homo opy) be ween up-maps (p-maps is a homo opy which is a up-map (p-map . Wi h [-, -], [-, -] P , and [-, -]  p we will ep- esen he se s o homo opy, p-homo opy and up-homo opy espec i ely . Also, he co esponding homo opy classes will be deno ed by [ ], [ ] p and [ ]up . R" will s and o he n-dimensional Euclidean space, and I o he uni in e al [0,1] wi h ha dis an e . The Euclidean no m will be ep esen ed by  - ~, and he dis an e o a me ic space by d(-, -) . This wo k has been suppo ed in pa by CAICYT g an 0812-84 12 4  R . AYALA, E . DOMINGUEZ, A . QUINTERO Theo em . Le X, Y, Z me ic spaces . We can de ine an injec i e map ID : Cup (X x Y, Z) -) Cup(X, Cü p (Y, Z)) as 1( ) (x) (y) = (x, y) . I X is compac , hen 1 is on o . P oo : I is easy o see ha : (a) Fo each x E X he map oD( )(x) is a up-map, because i is he composi- ion o wo up-maps . (b) oD ( ) is a u-map, because is a u-map . (c) Le us see ha 4>( ) is a p-map . Gi en a compac subspace K C Cú p (Y,Z), we only ha e o p o e ha any sequence {xn} in 1( ) -1 (K) has a clus e poin . Le {z,,} be a subsequence o {xj such ha {-D( ) (z n )} is con e gen ; le B E K be he limi poin . Then, o each yo E Y he sequence { (zn, yo)} con e ges o B(yo) . Consequen ly, H = { (zn, yo) ; n E N}U{e(yo)} is a compac subspace o Z . This implies ha he sequence {x,,} has a clus e poin . Hence -P is well de ined and i is an injec i e map . Since X is compac , each con inuous map de ined on X is also uni o mly con inuous . Then, gi en a con inuous map g : X -) Cú p (Y, Z) i is enough o show ha : X x Y-> Z de ined as (x, y) = g (x) (y) is a up-map . To p o e ha is a u-map, le ,, : Y -+ Z and , : X --> Z he maps de ined by = (y) = (x, y) = (x) o each couple (x, y) . Acco ding o [1, X .2 .1 .2] i su ices o show ha he se s H={ ., ;xEX} and C={ , ;yEY} a e uni o mly equicon inuous . Bu H = g (X) is a compac subse o Cú p (Y, Z), hence i is uni o mly equicon inuous by he heo em o Ascoli (see [1, .X .2 .5 .2]) . Since g is a up-map, i can be easily shown ha C is uni o mly equicon inuous se . I emains o show ha is a p-map . Le K be a compac subse o Z . I M = U{g(x)-'(K) ; xE X}, i is easy o check ha -1 (K) C X x M . I su ices o p o e ha M is a compac subse o Y . Gi en a sequence {y,,} in M, he e is a sequence {x,,} C X such ha g (x ,, ) (y,,) E K, o each n E N . Because X and K a e compac , we can assume ha {xn} and {g(xn)(yn)} con e ge o x o E X and zo E K espec i ely . Then, {g(xn)} con e ges o g(x o ), and i is ob ious ha o each e > 0 he e exis s n o such ha d(zo,g(xo)(yn)) < e i n >_ no . The e o e, K = {g(xo)(yn) ; n E N} U {zo} UNIFORMILY CONTINUOUS PROPER MAPS  12 5 is compac . Since g(x0) is p ope , g(xo) -1 (K) is also compac and {y,,} C g(xo) -1 (K) implies ha {y,,} has a clus e poin . We conclude ha M is compac . The ollowing s a emen is easily p o ed : Co olla y . Le X, Y, Z be me ic spaces . Mo eo e , suppose ha X is com- pac . Then, 1) <D : Cúp (X x, Y, Z) --> Cup (X, Cúp (Y, Z)) is up-isomo phism . 2) The se o pa h-componen s o Cú p (Y, Z) is in bijec i e co espondence wi h [Y, Z] up . 3) 1 induces a bijec i e co espondence 1 : [X x Y, Z]up -i [X, Cú p (Y, Z)] . Rema ks andExamples . I we conside only p ope maps, he na u al mapD : C p (X Z Y, Z) ---) C p (X, C p (Y, Z)) whe e C p (Y, Z) is endowed wi h he compac -open opology, is easily checked o be well de ined and injec i e . How- e e , se e al oubles appea : (1) The compac ness o X is necessa y in o de o p o e ha 1 is on o, e en i C p (Y, Z) is endowed wi h he uni o m con e gence opology . The ollowing example shows his ac : Le g : R -> C p (I, R) = C(I, R) be he map gi en by g(x) ( ) = x -(1- )x3 . I is easy o check he con inui y o g . In o de o p o e ha g is p ope , we ake a compac K C C(I,R) and a sequence {x  } C g -1 (K) . Then he e exis s a subsequence {z } o {x  }, such ha {g(zn)} con e ges o B E K . In pa icula , limg(z  )(1) = limz  = B(1) and we conclude ha g E Cp(R,C(I,R» . Bu he con inuous map (x, ) = g(x) ( ) is no p ope because «1' ) 21 , ) E -1 (0) o each E [0,1) . (2) Al hough X is compac , we canno ensu e ha 1D is on o i we conside he compac -open opology on C p (Y, Z) : Le g : I -)C p (R, R) gi en by g(0) (x) = go (x) = x and g( ) (x) = g (x) _ { ? x + 11  i 0 1/2 < x 1 / 2 _  (0 < < 1) . I is clea ha g E C p (R, R) o each E I . The con inui y o í ---> g ollows om he ac ha lim  = o in I implies ha {g } con e ges uni o mly on he compac subse s o Z o g o . Bu ( , x) -- g (x) is no a p ope map because ( ,1l ) E -1 (0) o each E (0,1] . (3) The p oo o he Theo em assu es ha 1 is on o i we conside he uni o m con e gence opology, u, on C p (Y, Z) and we assume he compac ness o X . Bu in such si ua ion, 1 :C p (X xY,Z) --+C(X,CP (Y, z» 12 6  R . AYALA, E . DOMINGUEZ, A . QUINTERO is no well de ined as shows he nex example : Le : I x R -> R 3 be he map ( , x) = ( , x, x) . This map is a p-map, and i 1( ) was con inuous and ,, -i o, gi en E > 0 he e would exis n o E N such ha i n > no x I I n - 0  1 :51 ( n , x, n x) - ( o' x, o x)  I < E o each x E R . Taking  x 1 la ge enough would yield he con adic ion E < x I I n  - o  I < E . The nex p oposi ion shows ha he e is no any possible duali y up- iso- mo phismwhen X is no compac . P oposi ion . Le Z be he open in e al (-1,1) . The e exis s no up-homo- opy equi alen e be ween C úp (R 2 , Z) and CúP (R, CúP (R, Z)) . We will need he ollowing lemma : Lemma .  The majo .1 : [Rn, Z]uP -> [Rn, Z] P gi en by A([ ]++p) = [ ] p is bijec i e . 1 P oo . I , g : Rn -> Z a e p-homo opic up-maps, he homo opy H : Rn x I -> Z gi en by H(x, ) = (x) + (1- )g(x) is a u-map . Now,we a e going o show ha H is p ope : Le K C Z be a compac subse and { n = (xn, ' ,» a seiluence in H -1 (K) . We may assume ha { n } con e ges o o . I we suppose ha { n }has no' clus e poin s we ha e lim x n = oo . Because and g a e p homo opic we ge lim (x n ) = limg(x n ) E {-1,1} . I his common limi s is 1 and U is an euclidean neighbou hood o 1 missing K, he e exis s n o such ha (xn),g(xn) E U o each n >_ n o . In pa icula , H(xn, n) E U  (n >_ no) con adic s he assump ion {(xn, n)} C H -1 (K) . So, A is an injec i e map . In o de o p o e ha A is on o we ecall ha [Rn, Z]p = [Sn -1 , S ° ], and i s elemen s a e he p-classes o he maps g_ 1 , g 1 : Rn -a Z gi en by g ; ( ) = ( j/(1+ 1 1)  (j = -1,1) i n > 2, o h( ), 1 h( ) 1, -h( ), - 1 h( ) i n = 1, whe e h( ) = (2/7 ) a c an( ) . This ollows, o ins an e, om he embedding heo ems o Edwa ds-Has ings, see [2, 6 .2 .7] . Now, a is on o because all he ep esen a i es a e up-maps . P oo o P oposi ion 4 : I su ices o p o e ha hose spaces ha e no he same numbe o pa h-componen e . As a consequence o Co olla y 2 .2) he pa h- componen s o Cú P (R 2 , Z) a e in bijec i e co espondence wi h [R 2 , Z]up . Bu [R 2 , Z]up - [R2, Z]p, by lemma 5, and he la e se has wo elemen s . Now,we a e going o show ha Cúp (R, Cúp (R, Z)) has a leas ou pa h- componen s . As aboye, Cúp (R, Z) has ou pa h-componen e, and hey a e he componen e o go (x) = (2/7 ) a c an(x),  91 = - 90, 92 =I g o I and g 3 = =- 1 go 1 .  Since Cúp (R, Z) is me izable and g o is a u-map,  o : R -~ Cú P (R, Z) de ined by o ( ) (x) = g o( + x) is a u-map .  Also, by using he UNIFORMILY CONTINUOUS PROPER MAPS  127 heo em o Ascoli i is easy o check ha o is a p-map . So, we ha e go a up-map o such ha o (R) lies in he pa h-componen o g o . In a simila way, we ge up-maps i wi h i (R) lying in he pa h-componen o gi (i = 1, 2, 3) . In pa icula , i and i a e no up-homo opic (0 <_ i =, 4 j < 3) . We conclude, applying co olla y 2 .2) again, ha he up-maps { ;}o< ;<3 de ine ou dis inc pa h-componen e . Rema k . I he me ic on Z is no bounded, lemma 5 is alse . Indeed, o each pai o eal numbe s a l , a 2 > 0, he up-maps l , 2 : R  ) R gi en by i ( ) = a  (i = 1, 2), a e p-homo opic, bu no up-homo opic : I H : R xI ---~ R is a up-homo opy be ween i and 2 , by [3, 111 .10] he e would exis e > 0 such ha H (x, ) - H (y, ') 1< max{e 1 (x, ) - (y, ') 1, e} o each couple (x, ), (y, ') E R x I . The e o e, la, -a2 1 x=1 i (x) - 2(x) j=j H(x, 0) - H(x,1) 1 :5E and aking x la ge enough he abo e inequali y would yield he con adic ion e<x1 al-a2 j< c . In ac , we ha e p o ed ha ca d [R, R]up > ca d R . Re e ences 1 .  N . BOURBAKI, in "Gene al Topology," He mann,1966 . 2 .  D . A . EDWARDS, H . M . HASTINGS, Cech and S een od Homo opy The- o y wi h applica ions o Geome ic Topology, Lec . No es 542 Sp inge (1976) . 3 .  J . R . ISBELL, Uni o m spaces, Ma h . Su eys, 12 AMS (1964) . R . Ayala : Dp o . d e Geome ía y Topología Facul ad de Ma emá icas 41012-Se illa, SPAIN . E . Dominguez : Dp o . d e Ma emá icas Facul ad de Ciencias Ciudad Uni e si a ia 50009-Za agoza, SPAIN . A . Quin e o : Dp o . d e Geome ía y Topología Facul ad de Ma emá icas 41012-Se illa, SPAIN . Rebu el 30 de Jung de 1987