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Chaotic scattering of He atoms off a Cu surface with corrugated Morse potential

Borondo, Florentino,Fontich Julià, Ernest,Martín de la Torre, Pablo

Abstract

We consider a Hamiltonian system that models the scattering of helium atoms off a copper surface. The interaction between the He and the Cu atoms is described by a corrugated Morse potential. Using corrugation coefficients values in the potential obtained by fitting to experimental values, we prove that, provided some coefficient of an auxiliary function is different from 0, there are regions of the phase space, corresponding to sufficiently large energy of the incident atom, where the scattering is chaotic. Furthermore, we prove that the system has oscillatory motions.

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a Xi :2401.05795 1 [ma h.DS] 11 Jan 2024 Chao ic sca e ing o He a oms o a Cu su ace wi h co uga ed Mo se po en ial Flo en ino Bo ondo∗ , E nes Fon ich† , and Pau Ma ín‡ . Janua y 12, 2024 Abs ac We conside a Hamil onian sys em ha models he sca e ing o helium a oms o a coppe su ace. The in e ac ion be ween he He and he Cu a oms is desc ibed by a co uga ed Mo se po en ial. Using co uga ion coe icien s alues in he po en ial ob ained by i ing o expe imen al alues, we p o e ha , p o ided some coe icien o an auxilia y unc ion is di e en om 0, he e a e egions o he phase space, co esponding o su icien ly la ge ene gy o he inciden a om, whe e he sca e ing is chao ic. Fu he mo e, we p o e ha he sys em has oscilla o y mo ions. Keywo ds: chao ic sca e ing, Hamil onian sys ems, oscilla o y o bi s, exponen ially small spli ing, inne equa ion. Con en s 1 In oduc ion 2 1.1 The He-Cu sca e ing p oblem. Main s a emen . . . . . . . . . . . . . . . . . . . . 2 1.2 Exponen ially small spli ing o in a ian mani olds . . . . . . . . . . . . . . . . . . 4 1.3 S uc u e o he pape .................................. 4 2 Hamil onian o mula ion o he He-Cu sca e ing p oblem and spli ing o sepa a ices 5 2.1 McGehee-like coo dina es and as dynamics ...................... 5 2.2 Dynamics o H0...................................... 6 2.3 The Melniko po en ial ................................. 8 2.4 Dynamics o he ull sys em. Spli ing o he in a ian mani olds . . . . . . . . . . 9 3 Chao ic dynamics 9 3.1 Poinca é-Ca an educ ion . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 10 3.2 Local coo dina es a ound q=p= 0 and a pa abolic λ-lemma . . . . . . . . . . . . 10 3.3 The local and he global maps . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 11 3.4 Symbolic dynamics. P oo o Theo em 1.1 . . . . . . . . . . . . . . . . . . . . . . . 12 4 Hamil on-Jacobi equa ion 14 4.1 No a ion .......................................... 14 4.2 De i ing he Hamil on-Jacobi equa ion . . . . . . . . . . . . . . . . . . . . . . . . . 15 4.3 De ini ions and echnical lemmas . . . . . . . . . . . . . . . . . . . . . . . . . . . . 16 4.4 Solu ion o he Hamil on-Jacobi equa ion (4.3) . . . . . . . . . . . . . . . . . . . . 18 ∗ .b[email p o ec ed], Depa amen o de Química, Uni e sidad Au ónoma de Mad id. † on [email protected], Depa amen de Ma emà iques i In o mà ica, Uni e si a de Ba celona (UB), and Cen e de Rece ca Ma emà ica (CRM). ‡[email p o ec ed], Depa amen de Ma emà iques, Uni e si a Poli ècnica de Ca alunya (UPC), and Cen e de Rece ca Ma emà ica (CRM) 1 5 Fi s ex ension o he in a ian mani old 20 5.1 F om Hamil on-Jacobi pa ame iza ion o low pa ame iza ion . . . . . . . . . . . 20 5.1.1 P elimina ies and echnical lemmas o sol e equa ion (5.6) . . . . . . . . . . 21 5.1.2 Solu ion o equa ion (5.6) . . . . . . . . . . . . . . . . . . . . . . . . . . . . 23 5.2 Ex ension o he low pa ame iza ion . . . . . . . . . . . . . . . . . . . . . . . . . 26 5.3 F om low pa ame iza ion o Hamil on-Jacobi . . . . . . . . . . . . . . . . . . . . 29 6 The inne equa ion 31 6.1 Spaces and echnical lemmas . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 32 6.2 Fixed poin equa ion ................................... 33 7 App oxima ion o he mani old in he inne domain 35 7.1 Spaces and echnical lemmas . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 38 7.2 The ixed poin equa ion ................................. 39 8 Di e ence be ween solu ions o he inne equa ion 41 9 Di e ence o he solu ions o he Hamil on-Jacobi equa ion 47 9.1 S aigh ening he linea ope a o . . . . . . . . . . . . . . . . . . . . . . . . . . . . 48 9.2 The exponen ially small o mula o Φ+−Φ−. . . . . . . . . . . . . . . . . . . . . 52 10 Acknowledgemen s 55 A P oo o Theo em 3.2 55 B P oo s o claims in Appendix A 59 B.1 P oo o Lemma A.1 ................................... 59 B.2 P oo o Lemma A.4 ................................... 60 B.3 P oo o Lemma A.5 ................................... 61 1 In oduc ion 1.1 The He-Cu sca e ing p oblem. Main s a emen We conside he mo ion o a helium a om bouncing o a coppe su ace. The p oblem a ises om expe imen al echniques, whe e he sca e ing o noble gas a oms a e collisions wi h a su ace is used o cha ac e ize su ace s uc u es in a non-des uc i e way [Hul92]. The co uga ion o he su ace is modeled by he e ec i e po en ial seen by he a oms as hey come nea he su ace. Co uga ion depends on he inciden ene gy: he highe he ene gy o he He a om, he close will ge o he su ace. Nume ical e idence o he exis ence o chao ic sca e ing was gi en in [GBMA97,BGB+99], whe e i was ela ed o some in a ian mani olds in he sys em. The pu pose o he p esen pape is o p o ide an ac ual igo ous p oo o such chao ic beha io , hus es ablishing a link be ween expe imen s and heo y on i m g ounds. We simpli y he p oblem assuming ha he He a om mo ion akes place on a plane; ac ually he ou -o -plane sca e ing is ela i ely small o he alues o he ene gies and inciden angles conside ed in he expe imen s. We deno e by (x, z)∈R2 he posi ion o he He a om, whe e xand za e he ho izon al and e ical displacemen s, espec i ely. Le (px, pz)be he conjuga e momen a. We model he in e ac ion o he He a om wi h he coppe su ace by a co uga ed Mo se po en ial, whe e he co uga ion ep esen s he p esence o he coppe a oms in he su ace. Mo e conc e ely, we conside he Hamil onian HCM(x, z, px, pz) = 1 2m(p2 x+p2 z) + VM(z) + VC2πx a, z,(1.1) whe e VM(z) = De−αz(e−αz −2), VC(θ, z) = De−2αz V(θ), V(θ) = X n≥1 ( ncos(nθ) + snsin(nθ)) . (1.2) 2 The coe icien s nand sna e de e mined expe imen ally. Thei alues a e 1= 0.06, 2= 0.008, n= 0, n ≥3, sn= 0, n ≥1, D= 6.35 meV, a= 3.6Å, α= 1.05 Å−1. See [GBMA97]. In pa icula , 16= 0. In he p esen pape , ou only equi emen on Vis ha i is an analy ic e en unc ion, ha is, sn= 0, o all n. We emphasize ha we do no equi e V o be a igonome ic polynomial. E enness is no an impo an equi emen and he esul s will hold wi h he same echniques o non-e en V, bu he added symme y will simpli y some o he de ails, pa icula ly he nume ical compu a ions pe o med in he p oblem ha a e ca ied ou in [BBF+23]. Since θ= 2πx/a appea s in he equa ion h ough V, we will ake θ∈T=R/2πZ. The pu pose o his pape is wo old. On he one hand, we wan o p o e he p esence o chaos in some pa s o he phase space o (1.1). He e, he no ion o chaos is he one in oduced by Smale in [Sma65] and i is based on he p esence o a Smale ho seshoe and a conjuga ion wi h he shi on a space o sequences o symbols. I is wo h o ema k ha he se whe e chaos akes place is a hype bolic se . We ecall he de ini ion o symbolic dynamics wi h an in ini e numbe o symbols, as in oduced by Mose in [Mos73]. Le S={s= (...,s−1, s0, s1,...)|si∈N}be he space o wo sided sequences o in ini e symbols, wi h he opology induced by he neighbo hood basis o s∗= (...,s∗ −1, s∗ 0, s∗ 1,...), Ij(s∗) = {s∈S|sk=s∗ k,|k|< j}, s∗∈S. I is well known ha he shi σ:S→Sde ined by σ(s)i=si+1 is a homeomo phism. The shi σis ansi i e and he se o i s pe iodic o bi s is dense in S. I has sensi i e dependence on ini ial condi ions. I is one o he pa adigms o chaos. The second goal o he pape is o p o e he exis ence o oscilla o y o bi s, ha is, solu ions (x( ), z( )) o (1.1) wi h he p ope y ha lim sup z( ) = ∞and lim in z( )<∞, ha is, solu ions ha go highe and highe bu always go back again o a ini e dis ance o he Cu su ace. The claims in he p esen pape ollow he scheme p oposed by Mose in [Mos73], which was also used in he es ic ed plana h ee body p oblem in [LS80]. In his las pape , an impo - an echnicali y, no p esen in Mose ’s wo k, appea ed: he exponen ially small beha io o he di e ence be ween he mani olds which gi e ise o he in e es ing dynamics. This p oblem was la e o e come in [GMS16]. This exponen ially small beha io also appea s in he model unde conside a ion he e and dealing wi h i will ep esen an impo an pa o ou wo k. Ou main heo em is he ollowing. Theo em 1.1. The e exis s a unc ion 1o he coe icien s 1, 2,... such ha i 16= 0, hen, o any hla ge enough, he e exis s a sec ion Σ⊂ {HCM =h}o he ec o ield associa ed o HCM and a subse I ⊂ Σsuch ha he Poinca é map Ψ : I → I is a homeomo phism and is conjuga e o he shi σo in ini e symbols. The se Iis a hype bolic se o Ψ. Fu he mo e, o any hla ge enough, he Hamil onian HCM in (1.1)possesses oscilla o y o bi s. Rema k 1.2. The unc ion 1appea s in a p oblem independen o he ene gy h. This equa ion is usually known in he li e a u e as inne equa ion. The nume ical e idence in [BBF+23] s ongly sugges s ha o he expe imen al alues men ioned abo e, 1is non-ze o. Fu he mo e, we p o e ha i one eplaces iby ε˜ iin he de ini ion o V, in (1.2), ha is, i we conside he e m VCas a small pe u ba ion, hen 1=επ 4˜ 1+O(ε2). The es o he pape is de o ed o p o e Theo em 1.1. In pa icula , i will be an immedia e consequence o Theo em 3.5. We would like o ema k ha he hype bolic se , as is he case o he Si niko p oblem conside ed in [Mos73] o he es ic ed plana h ee body p oblem in [LS80,GMS16], is ela ed o he in a ian mani olds o a ce ain pe iodic o bi a z=∞. In ou case, since he equa ions o mo ion a e ˙x=1 mpx, ˙z=1 mpz, ˙px=−2π aDe−2αzV′2πx a, ˙pz=−2Dα e−αz 1−e−αz 1 + V2πx a, (1.3) 3 we ha e ha he se {(x, z, px, pz)∈R/aZ×R×R2|z=∞, pz= 0, px= (2mh)1/2}(1.4) is a pe iodic o bi o (1.3) a in ini y in he ene gy le el h. The p oo o Theo em 1.1 consis s in checking ha his pe iodic o bi possesses in a ian s able and uns able mani olds, ha hese in a ian mani olds in e sec ans e sally i his la ge enough and hen p o e a sui able λ-lemma ha ensu es ha his ans e sal in e sec ion gi es ise o he s anda d isola ing blocks wi h cone condi ions. This las pa is due o he ac ha he pe iodic o bi (1.4) is nei he hype bolic no ellip ic, bu degene a e. Howe e , al hough degene a e, i possesses s able and uns able in a ian mani olds. The s udy o he in a ian mani olds o hese ype o degene a e objec s goes back o [McG73]. See also [BFdlLM07], whe e he pa ame iza ion me hod is used, and he subsequen wo ks, [BFM20a,BFM20b,BFM17,BFM20c]. In his case, when he pe iodic o bi is degene a e, he s anda d λ-lemma does no hold. In pa icula , i is no ue ha he o wa d images o a mani old in e sec ing ans e sally he s able mani old o he o bi accumula e o he whole uns able mani old. Hence, a di e en a gumen is needed o con ol he passage close o he pe iodic o bi . This was al eady known by Mose in [Mos73]. Howe e , his p oo does no di ec ly apply o he p esen case, because he deg ee o degene acy o ou case is di e en om he one o he Si niko p oblem. We p esen ano he p oo , based in he ideas in [GMPS22]. 1.2 Exponen ially small spli ing o in a ian mani olds One o he main di icul ies o he p esen wo k is o es ablish ha he angle o in e sec ion be ween he s able and uns able in a ian mani olds o ce ain pe iodic o bi s is non-ze o. Indeed, since ou goal is o deal wi h he physical p oblem, in which he co uga ion, modelled by he unc ion V in (1.2), is ixed, he only pa ame e we will ha e o deal wi h he p oblem will be he ene gy o he sys em. We will see ha he angle o in e sec ion is in ac exponen ially small in he ene gy hence p ecluding he use o he s anda d Melniko heo y. S a ing wi h he seminal pape o Lazu kin [Laz84] (see he English ansla ion in [Laz03]), he e is a long lis o wo ks in he li e a u e conce ning he exponen ially small spli ing o sepa a- ices. In pa icula , he me hod in oduced in [Sau01] has been essen ial in pos e io de elopmen s o he ield. See [BFGS12] and he e e ences he ein. Ou app oach he e is simila o he he one es ablished in [BFGS12] and [Bal06]. I is impo an o ema k ha he esul s in hese las wo pape s do no apply o ou se ing. As a ma e o ac , i one ies o w i e Hamil onian (1.1), which has 2 deg ees o eedom, as a 11 2deg ees o eedom one using he Poinca é-Ca an e- duc ion, he educed Hamil onian does no sa is y some o he hypo heses in [BFGS12,Bal06]. Pa icula ly, when w i en as an in eg able Hamil onian plus a pe u ba ion, he pe u ba ion is no polynomial and has b anching singula i ies when ex ended o he complex domain. This is ue e en in he McGehee a iables ha a e in oduced in Sec ion 2. Since we a e no assuming he pe u ba ion o be small, we need o s udy he inne equa ion associa ed o he p oblem in o de o cap u e he leading e m o he exponen ially small beha io o he spli ing. This inne equa ion was used by Gel eich in [Gel99] o p o e he spli ing o sepa ices in he Chi iko s anda d map. See also [MSS11a,MSS11b], whe e he McMillan map was s udied by using esu gence heo y. The s udy o he inne equa ion o he Hénon map was pe o med in [GS01]. The exponen ially small spli ing o in a ian mani olds also appea s in o he physical p oblems, since i is ela ed o he exis ence o some as equencies on he sys em. In pa icula , i has been deal wi h success ully in some p oblem o celes ial mechanics [GMS16,GMPS22,GPS23]. In hese las cases, howe e , he Melniko unc ion p edic s co ec ly he i s o de o he spli ing. 1.3 S uc u e o he pape The s uc u e o he pape is as ollows. In Sec ion 2we w i e he sys em in sui able McGehee coo dina es, desc ibe he geome ic beha iou o i and claim he main heo em o he spli ing o sepa a ices. In Sec ion 3we apply he spli ing heo em o deduce he exis ence o chao ic dynamics o he sys em. To do so, we need o cope wi h he p oblem ha he pe iodic o bi s unde conside a ion a e no hype bolic bu degene a e, which implies ha he s anda d lambda lemma does no apply. 4 He e we use a e sion o he pa abolic lambda lemma in [GMPS22] o ob ain he conjuga ion o he Be noulli shi . Sec ions 4 o 9deal wi h he ac ual spli ing o he in a ian mani olds o he pe iodic o bi a in ini y. In Sec ions 4and 5we ob ain sui able app oxima ions o he in a ian mani olds by sol ing an app op ia e Hamil on-Jacobi equa ion. These app oxima ions a e alid in a ce ain complex domain. Howe e , we a e no able o ob ain enough in o ma ion o hei di e ence. To do so, we in oduce he inne equa ion in Sec ion 6, om which we ob ain wo solu ions. In Sec ion 7, we check ha hese solu ions a e also good app oxima ions o he in a ian mani olds in some egion o hei complex domain o de ini ion. In Sec ion 8we ob ain an exponen ially small o mula o he di e ence o solu ions o he inne equa ion which, in u n, we use in Sec ion 9 o ob ain he exponen ially small o mula o he di e ence o he in a ian mani olds. We ha e le o Appendix A he p oo o he pa abolic lambda lemma (Theo em 3.2). Ap- pendix B.1 con ains he p oo s o some echnical lemmas used in he p oo o Theo em 3.2. 2 Hamil onian o mula ion o he He-Cu sca e ing p oblem and spli ing o sepa a ices 2.1 McGehee-like coo dina es and as dynamics We a e in e es ed in mo ions o which he He pa icle a i es o z=∞wi h ze o momen um. Fo his eason, we in oduce he McGehee-like coo dina es    Aq2=e−αz,a 2πθ=x, Bp =pz, CI =px, whe e A= 2, B =aα 4πC, C2= 2mD 8π aα2 . Wi hou loss o gene ali y, we ake C > 0. This change ans o ms he s anda d 2- o m dx ∧dpx+ dz ∧dpzin o he b-symplec ic o m (aC/2π)ω, whe e ω=dθ ∧dI −1 qdq ∧dp (2.1) and he Hamil onian unc ion HCM in (1.1) becomes 8D·H, whe e H(q, p, θ, I) = 1 2(νI2+p2)−1 2q2+1 2q4+1 2q4V(θ)(2.2) and ν=4π aα2 . Fo he expe imen al alues o he He-Cu p oblem, he alue o νis ν= 11.051879175935... Rescaling ime, he dynamics o HCM is equi alen o he one gene a ed by Hwi h espec o he o m ω. To s udy he beha io o he sys em o la ge alues o I0, we in oduce he new a iable J by I=I0+Jin (2.2) wi h I0≫1. This change p ese es he 2- o m ω. We will deno e he Hamil onian in hese new a iables wi h he same le e , namely, H(q, p, θ, J) = H0(q, p, J) + H1(q, p, θ, J),(2.3) whe e H0(q, p, J) = 1 2(ν(I0+J)2+p2)−1 2q2+1 2q4, H1(q, p, θ, J) = 1 2q4V(θ). (2.4) 5 Since H0does no depend on θ, i is in eg able. We ema k ha Hlooks like a pe iodically pe u bed Du ing equa ion. Howe e , since he ec o ield gene a ed by His ob ained h ough he non-s anda d 2- o m ω, he sys em is no equi alen o he Du ing equa ion. Indeed, he equa ions o mo ion gene a ed by Ha e ˙q=−q∂H ∂p =−qp, ˙ θ=∂H ∂I =νI0+νJ, ˙p=−q−∂H ∂q =−q2+ 2q4+ 2q4V(θ),˙ J=−∂H ∂θ =−q4 2V′(θ), (2.5) which is no a Du ing oscilla o due o he p esence o he ac o qin he (q, p)componen s o he ec o ield. We conside , a he ene gy le el νI2 0/2o Hin (2.3), he se ΛνI0={q=p=J= 0, θ ∈T}. F om (2.5), i is in a ian and he dynamics on ΛνI0is gi en by θ=θ0+νI0 , ha is, i is pe iodic wi h equency νI0/(2π), which is as when νI0is la ge. Tha is, a he ene gy le el νI2 0/2, o la ge alues o νI0,Hcan be seen as a as pe iodic pe u ba ion o he in eg able Hamil onian H0. We emphasize ha he pe u ba ion H1is no small since we a e assuming ha 1is ixed and we will conside mo ions in which qwill each size o O(1). The p oo o Theo em 1.1 consis s in p o ing ha each o hese pe iodic o bi s possesses in a ian mani olds and ha hey in e sec ans e sally. F om his in e sec ion we will deduce he exis ence o a ho seshoe wi h in ini ely many symbols. Howe e , since he sys em is a as pe iodic pe u ba ion o an in eg able sys em, i is well known ha he angle o in e sec ion o he mani olds will be smalle han any powe o he in e se o he equency which makes he ques ion o compu ing i a beyond all o de s phenomenon. Rema k 2.1. Al hough H1is no small, i is well known ha he ac ha depends on a as angle implies ha i s con ibu ion a e ages ou up o an exponen ially small emainde . Indeed, we can apply a s ep o a e aging and s ill ob ain an explici exp ession o he emainde , which is o size O((νI0)−1). I is immedia e o check ha he change θ= Θ, J =K+A′(Θ)Q4, q =Q, p =P+ 4A(Θ)Q4, p ese es he 2- o m ωin (2.1). In hese new a iables, Hbecomes e H(Q, P, Θ, K) =1 2(ν(I0+K−A′(Θ)Q4)2+ (P+ 4A(Θ)Q4)2)−1 2Q2+1 2Q4+1 2Q4V(Θ) =1 2(ν(I0+K)2+P2)−1 2Q2+1 2Q4+1 2V(Θ) −νI0A′(Θ)Q4 −νA′(Θ)KQ4+ 4A(Θ)PQ4+ 8A(Θ)2Q8+1 2νA′(Θ)2Q8. Taking Asuch ha A′(Θ) = −V(θ)/(2νI0)and in oducing W(Θ) = RΘV(ϑ)dϑ, we ob ain e H(Q, P, Θ, K) = H0(Q, P, K) + e H1(Q, P, Θ, K), whe e e H1(Q, P, Θ, K) = 1 2νI0−νV (Θ)KQ4+ 4W(Θ)PQ4+1 4I0 V(Θ)2Q8+4 νI0 W(Θ)2Q8. The compu a ions o he Melniko po en ial in Sec ion 2.3 below lead o a o mula o he same o de . We will no ollow his app oach. On he con a y, we will wo k di ec ly wi h he Hamil onian H=H0+H1in (2.3). 2.2 Dynamics o H0 In iew o Rema k 2.1, al hough H1is no small, we can see H0as a e e ence sys em o H. He e we desc ibe i s dynamics. Fi s we obse e ha , since H0does no depend on θ,Jis a conse ed quan i y. Hence, H0is in eg able. Using he 2- o m ωin (2.1), he equa ions o mo ion o H0a e ˙q=−qp, ˙ θ=νI0+νJ, ˙p=−q2+ 2q4,˙ J= 0.(2.6) 6 The se ΛνI0={q=p=J= 0, θ ∈T} is a pe iodic o bi in {H0=νI2 0/2}. F om (2.6), as we ha e al eady men ioned, i is clea ha he es ic ion o ΛνI0 o {H0=νI2 0/2, J = 0}is no hype bolic. Howe e , i possesses in a ian s able and uns able mani olds, ha gene a e wo homoclinic loops, gi en by W0 νI0=(q, p, θ, J)|J= 0, θ ∈T, H0(q, p, 0) = 1 2νI2 0. See Figu e 1. We will ocus on he loop wi h q≥0. The igu e is sligh ly misleading: o any J, he se {q= 0, p =p0}is a pe iodic o bi . In pa icula , {q= 0}is in a ian , e en o he ull Hamil onian H. This means ha , in ac , in he (q, p)-plane, (q, p) = (0,0) is no a opological saddle because, in pa icula , is no an isola ed equilib ium poin because q= 0 is a line o equilib ia. As a consequence, he s anda d λ-lemma is no longe ue and ano he s a emen will be necessa y. The needed esul is Theo em 3.2 below. We will be in e es ed in he pa o he phase space whe e q > 0. Figu e 1: The p ojec ion o he in a ian mani olds W0 νI0on o he (q, p)-plane. Fo each p=p0, {(0, p0, θ, 0) |θ∈T}is a pe iodic o bi . The ollowing lemma, whose p oo is a s aigh o wa d compu a ion, p o ides he ime pa ame- iza ion o he igh hand side homoclinic o bi . Lemma 2.2. The ime pa ame iza ion o he homoclinic o bi o (0,0) o (H0)|J=0 ha passes h ough (1,0) a = 0 is gi en by qh( ) = 1 √1 + 2, ph( ) = −˙qh( ) qh( )= 1 + 2. As a consequence, Γ0(u, θ) =     qh(u) ph(u) θ 0    (2.7) pa ame izes W0 νI0. Deno ing φ0 he low gene a ed by H0, his pa ame iza ion sa is ies φ0 ◦ Γ0(u, θ) = Γ0(u+ , θ +νI0 ). 7 2.3 The Melniko po en ial As usual, we de ine he Melniko po en ial associa ed o he Hamil onian Has L(u, θ) = −Z∞ −∞ H1(qh(u+ ), ph(u+ ), θ +νI0 , 0) d . (2.8) Expanding Vin Fou ie se ies, V(θ) = X k∈Z V[k]eikθ, by (2.4), we can w i e H1(q, p, θ, 0) = q4 2V(θ) = q4 2X k∈Z V[k]eikθ. Since Vis eal analy ic, e en and has ze o a e age, we ha e ha V[k]∈R, V [0] = 0, V [k]=V[−k], k ∈Z {0} and he e exis s σ0>0and K > 0such ha , o all k∈Z, |V[k]| ≤ Ke−|k|σ0.(2.9) Hence, L(u, θ) = −Z∞ −∞ H1(qh( ), ph( ), θ −νI0u+νI0 , 0) d =−X k∈Z eik(θ−νI0u)Z∞ −∞ q4 h( ) 2V[k]eikνI0 d . Tha is, L(u, θ) = X k∈Z L[k](νI0)eik(θ−νI0u), whe e L[k](νI0) = −1 2V[k]Z∞ −∞ q4 h( )eikνI0 d . P oposi ion 2.3. The Melniko po en ial Lsa is ies L[k](νI0) = −πνI0V[k] 4e−|k|νI0|k|+1 νI0, k ∈Z. In pa icula , since V[0] = 0 hen L[0](νI0) = 0. P oo . Since, in iew o Lemma 2.2,q4 his a me omo phic unc ion ha has poles o o de 2a ±i, he claim ollows om a s aigh o wa d esidue compu a ion. Co olla y 2.4. I 16= 0 in (1.2), hen L(u, θ) = −π 4νI0 1e−νI01 + 1 νI0cos(θ−νI0u) + O(e−νI0). I he coe icien s iin he de ini ion o Vin (1.2) sa is y i=ε˜ iand ˜ 16= 0, he s anda d Melniko heo y implies ha he dis ance be ween he uns able and s able in a ian mani olds o ΛνI0is gi en by he de i a i es o εL plus an e o o size O(ε2). Howe e , since Lhas size O(e−νI0), his means ha a he ene gy le el νI2 0/2,εL gi es he leading o de o he dis ance only i ε < O(e−νI0), ha is, o a ixed alue o he ene gy, he in a ian mani olds o in ini y spli only i he co uga ion is exponen ially small in he ene gy. We will see ha εand νI0can be aken as independen pa ame e s while he exponen ially small o mula o he dis ance will emain alid. The physical implica ions a e impo an : we will see ha , o a gi en co uga ion, i ce ain coe icien is di e en om 0( ha depends on he coe icien s o he co uga ion and is gene ically non-ze o), o any la ge enough ene gy, he in a ian mani olds o in ini y spli . Mo eo e , his coe icien depends on i s o de on L[1] i εis small. I is impo an o ema k ha i 1= 0, he Melniko unc ion is o o de e−2νI0. Howe e , in his case, he ue beha io , gi en by o mula (2.11) in Theo em 2.5, below, can be o o de e−νI0, i ce ain coe icien 1is di e en om 0. See [BMS23]. 8 2.4 Dynamics o he ull sys em. Spli ing o he in a ian mani olds The pe iodic o bi ΛνI0={q=p=J= 0, θ ∈T}o H0 emains when we conside he ull sys em Hin (2.3), wi h he same equency νI0. Al hough i is no hype bolic, we will p o e ha i has in a ian uns able and s able mani olds, which, i ce ain non-degene acy condi ion holds, no longe coincide. Nex heo em summa izes he claim. I is he i s s ep in he p oo o Theo em 1.1. Theo em 2.5. I νI0is la ge enough, he pe iodic o bi ΛνI0={q=p=J= 0, θ ∈T}possesses in a ian uns able and s able mani olds, W± νI0. Mo eo e , o any 0< u0< u1, he e exis analy ic unc ions Φ±: [u0, u1]×T→Rsuch ha Γ±(u, θ) =     qh(u) ph(u)−1∂uΦ±(u, θ) θ ∂θΦ±(u, θ)    (2.10) a e pa ame iza ions o pieces o W± νI0sa is ying (1) Γ±= Γ0+O((νI0)−1), whe e Γ0is gi en in (2.7), (2) he e exis s 1,Λ0∈Rsuch ha , o any j, k ≥0,0≤j+k≤3, ∂j u∂k θ(Φ+(u, θ)−Φ−(u, θ)−Λ0) = (−1)j(νI0)j+1e−νI02 1∂j+k αcos α|α=(θ−νI0u)+O1 log(νI0).(2.11) The coe icien s 1and Λ0do no depend on νI0. They only depend on he coe icien s io he unc ion Vin H1. I one assumes ha i=ε˜ i, i.e. he co uga ion e m H1is a small pe u ba ion o H0, hen 1=π 2˜ 1ε+O(ε2).(2.12) Rema k 2.6. Fo he expe imen al alues o Vco esponding o he in e ac ion be ween helium and coppe a oms, nume ical expe imen s in [BBF+23] sugges ha 16= 0. Howe e , i i=ε˜ i, we will see ha 1is an analy ic unc ion o ε. Then, (2.12)implies ha , i ˜ 16= 0, 1can only anish o a disc e e numbe o alues o ε. Co olla y 2.7. I νI0is la ge enough, he in a ian mani olds W± νI0o ΛνI0in e sec ans e sely along wo p ima y homoclinic o bi s. P oo . Since W± νI0a e con ained in he le el νI2 0/2o H, he exp ession o Γ±in (2.10) implies ha hei in e sec ions a e gi en by ∂uΦ+(u, θ)−∂uΦ−(u, θ) = 0. Then, (2.11) allows us o apply he s anda d implici unc ion heo em o ob ain ha he p ima y homoclinic o bi s a e gi en by θ−νI0u+O((νI0)−1) = kπ. Theo em 2.5 p o ides an exponen ially small o mula o he di e ence o he in a ian mani olds W± νI0, wi h he ene gy o he sys em as pa ame e . We will ind sui able app oxima ions o he in a ian mani olds o ΛνI0which ex end o complex alues o hei a iables. The leading e m o hese app oxima ions, o bo h he s able and uns able mani olds, will be he unpe u bed sepa a ix Γ0. This is done in Sec ions 4and 5. In many cases, his is enough o ob ain he exponen ially small o mula, whose leading e m is gi en by he Melniko po en ial (2.8). He e, howe e , in o de o cap u e he leading e m o he exponen ially small di e ence be ween he mani olds, we need o eso o wha is o en known as he inne equa ion. This is done in Sec ion 6 and 8. In Sec ion 7 he mani olds a e compa ed wi h he solu ions o he inne equa ion and, inally, all he in o ma ion is ga he ed in Sec ion 9, comple ing he p oo o Theo em 2.5. 3 Chao ic dynamics He e we de ine a e u n map on a sui able sec ion such ha i possesses an in a ian hype bolic se and when es ic ed o his se , i is opologically conjuga e o he shi o in ini e symbols. The cons uc ion is analogous o he one o Mose in [Mos73]. 9 equa ion (4.6) becomes L(Φ1) = F(Φ1).(4.9) We ema k ha F(0)(u, θ) = −H1(qh(u), θ) = −1 2 1 (1 + u2)2V(θ).(4.10) To sol e (4.9), we will ew i e i as a ixed poin equa ion by means o a sui able igh in e se Go L, o be de ined la e on, ha is, Φ1=G ◦F(Φ1).(4.11) We will de o e he es o he sec ion o p o e he exis ence o a solu ion o (4.6) wi h he bounda y condi ions as u→ −∞ in (4.4). 4.3 De ini ions and echnical lemmas Le 0< β1< β2< π/2be ixed. Fo κ > 1and δ∈(0,1/2), we conside he complex domain D+ κ,δ ={u∈C| |ℑu|<− an β1ℜu+ 1 −κ(νI0)−1,|ℑu|> an β2ℜu+ 1 −δ.(4.12) We will be in e es ed in he case whe e I0and κa e big bu sa is y κ(νI0)−1< δ. Obse e ha , i κ(νI0)−1< δ, hen d(D+ κ,δ,±i) = Cκ(νI0)−1wi h C= cos β1. See Figu e 2. Figu e 2: The domain D+ κ,δ de ined in (4.12). To sol e equa ion (4.9), o , s ∈Rwe in oduce he Banach space o eal analy ic, 2π-pe iodic in θ, unc ions X ,s ={Ψ : D+ κ,δ ×Tσ→C|Ψ eal analy ic,kΨk ,s <∞} and, aking in o accoun he Fou ie expansion Ψ(u, θ) = Pk∈ZΨ[k](u)eikθ, he no m kΨk ,s =X k∈ZkΨ[k]k ,se|k|σ, whe e, o an analy ic unc ion :D+ κ,δ →C, k k ,s = max   sup u∈D+ κ,δ,ℜu≤−u0|u (u)|,sup u∈D+ κ,δ,ℜu>−u0|(1 + u2)s (u)|  , whe e u0∈Ris chosen such ha u0≥max{1,(1 −δ)/ an β2}. 16 Lemma 4.2. Le , 1, 2, s, s1, s2∈R. We ha e (1) I Ψ∈ X + 1,s+ 2wi h 1, 2≥0 hen Ψ∈ X ,s and kΨk ,s ≤KνI0 κ 2 kΨk + 1,s+ 2, whe e K > 0is independen o νI0and κ. (2) I Ψ1∈ X 1,s1and Ψ2∈ X 2,s2 hen Ψ1Ψ2∈ X 1+ 2,s1+s2and kΨ1Ψ2k 1+ 2,s1+s2≤ kΨ1k 1,s1kΨ2k 2,s2. The p oo o he p e ious lemma is s aigh o wa d om he ideas in [Sau01]. We also in oduce e X ,s ={Ψ∈ X ,s |∂uΨ∈ X +1,s+1, ∂θΨ∈ X +1,s+1,TΨU ,s <∞}, whe e TΨU ,s =kΨk ,s +k∂uΨk +1,s+1 +νI0k∂θΨk +1,s+1. Gi en Ψ∈ X ,s, wi h > 0,s≥0, we o mally de ine Gu(Ψ)(u, θ) = Z0 −∞ Ψ(u+ξ, θ +νI0ξ)dξ =Zu −∞ Ψ(ξ, θ +νI0(ξ−u)) dξ. (4.13) Clea ly, when Gu(Ψ) is well de ined, i Ψis eal analy ic, so is Gu(Ψ). The ope a o Gu o mally sa is ies L◦Gu(Ψ) = Ψ, whe e Lis he di e en ial ope a o in oduced in (4.7). The nex echnical lemma will be he main ool o ind he desi ed solu ions o equa ion (4.11). I s p oo is an immedia e a ia ion o he a gumen s in [GOS10]. Lemma 4.3. Le Gube he ope a o de ined in (4.13). (1) I Ψ∈ X ,s, wi h > 1,s≥0, hen Gu(Ψ) ∈ X −1,s and kGu(Ψ)k −1,s ≤KkΨk ,s. I , s > 0and hΨi= 0, hen Gu(Ψ) ∈ X ,s and kGu(Ψ)k ,s ≤K(νI0)−1kΨk ,s. (2) I Ψ∈ X ,s, wi h , s > 1,Gu(Ψ) ∈ X −1,s−1and kGu(Ψ)k −1,s−1≤KkΨk ,s. (3) I Ψ∈ X ,s, wi h ≥1,s > 0,∂uGu(Ψ), ∂θGu(Ψ) ∈ X ,s and k∂uGu(Ψ)k ,s ≤KkΨk ,s,k∂θGu(Ψ)k ,s ≤K(νI0)−1kΨk ,s. As a consequence, i Ψ∈ X ,s, wi h , s > 1,Gu(Ψ) ∈e X −1,s−1and TGu(Ψ)U −1,s−1≤KkΨk ,s. The cons an Konly depends on , s and he cons an s in ol ed in he de ini ion o D+ κ,δ bu i is independen o νI0and κ. 17 4.4 Solu ion o he Hamil on-Jacobi equa ion (4.3) Le Fand Gube he ope a o s de ined by (4.8) and (4.13), espec i ely. We o mally in oduce L+ ou (u, θ) = Gu◦F(0)(u, θ) = −Zu −∞ H1(qh(s), θ +νI0(s−u)) ds =−Zu −∞ 1 2(1 + s2)2V(θ−νI0(s−u)) ds. (4.14) Fo la e use we also in oduce L− ou (u, θ) = −L+ ou (−u, −θ) = Z∞ u 1 2(1 + s2)2V(θ+νI0(s−u)) ds and Lou (u, θ) = L+ ou (u, θ)−L− ou (u, θ) = −Z∞ −∞ 1 2(1 + s2)2V(θ+νI0(s−u)) ds. Obse e ha Lou =L, whe e Lis he Melniko po en ial in oduced in (2.8). P oposi ion 4.4. The unc ion L+ ou ∈ X4,2in D+ κ,δ and sa is ies kL+ ou k4,2,k∂θL+ ou k4,2,k∂uL+ ou k5,3≤K νI0 , o some K > 0, independen o νI0and κ. Fu he mo e, hL+ ou i= 0. P oo . We ecall ha F(0)(u, θ) = −H1(qh(u), θ) = −1 2q4 h(u)V(θ) = −1 2 1 (1 + u2)2V(θ), whe e H1was in oduced in (2.4) and he unc ion Vin (1.2). Clea ly, F(0) ∈ X4,2and hF(0)i= 0. The bounds on kL+ ou k4,2and on k∂θL+ ou k4,2 ollow om (1) and (3) o Lemma 4.3, espec i ely. To ob ain he bound on k∂uL+ ou k5,3we obse e ha , by in eg a ion by pa s, i k6= 0, ∂uZu −∞ 1 2 1 (1 + s2)2eikνI0(s−u)eikθ ds =−2Zu −∞ s (1 + s2)3eikνI0(s−u)eikθ ds. Hence, de ining g(u, θ) = −2u (1 + u2)3V(θ), we ha e ha ∂uL+ ou =Gu(g). Since hgi= 0 and g∈ X5,3, using again (1) o Lemma 4.3, k∂uL+ ou k5,3=kGu(g)k5,3≤K(νI0)−1kgk5,3. The las claim ollows om he ac ha hF(0)i= 0. We use L+ ou o ew i e equa ion (4.11) as a new ixed poin equa ion, wi h be e con ol o i s solu ion. To do so, we in oduce Φ2by Φ1=L+ ou + Φ2. Then, Φ1is a solu ion o (4.11) i and only i Φ2sa is ies Φ2=Gu◦e F(Φ2), whe e e F(Φ2) = F(L+ ou + Φ2)−F(0).(4.15) P oposi ion 4.5. The e exis s K∗>0such ha , i κis big enough, he ope a o Gu◦e F: BK∗(νI0)−2⊂e X5,3→ BK∗(νI0)−2is well de ined and a con ac ion. Le Φ+ 2be i s ixed poin . As a consequence, since Φ+ 2is he ixed poin o Gu◦e F, hen Φ+ 1=L+ ou + Φ+ 2is a solu ion o equa ion (4.9). 18 P oo . We i s claim ha e F(0) ∈ X6,4and ke F(0)k6,4≤K1(νI0)−2, o some K1independen o νI0. Indeed, by he de ini ions o Fin (4.8) and e Fin (4.15), using Lemma 4.2, P oposi ion 4.4, he ac ha p−2 h∈ X−2,−2and k∂θL+ ou k2,2≤ k∂θL+ ou k4,2≤K νI0 , we ha e ha ke F(0)k6,4= 1 2p2 h (∂uL+ ou )2+ν 2(∂θL+ ou )26,4 ≤ 1 2p2 h ∂uL+ ou 1,1k∂uL+ ou k5,3+ν 2k∂θL+ ou k2,2k∂θL+ ou k4,2 ≤K 2kp−2 hk−2,−2k∂uL+ ou k3,3 1 νI0 +νK 2k∂θL+ ou k2,2 1 νI0 ≤K2 2kp−2 hk−2,−2 1 (νI0)2+νK2 2(νI0)2 ≤K1 (νI0)2. Hence, by he las claim o Lemma 4.3,TGu◦e F(0)U5,3≤Kke F(0)k6,4≤KK1 (νI0)2<∞. We ake K∗= 2KK1. Le Ψ∈ BK∗(νI0)−2⊂e X5,3. In iew o (4.8) and (4.15), we w i e e F(Ψ) = e F(0) + e F(Ψ) −e F(0) = F0−F1−F2, whe e F0=e F(0), F1=1 2p2 h(∂uL+ ou +∂uΨ)2−(∂uL+ ou )2, F2=ν 2(∂θL+ ou +∂θΨ)2−(∂θL+ ou )2. We s a wi h F1. Using ha kp−2 hk−2,−2<∞,k∂uL+ ou k5,3≤K(νI0)−1,Ψ∈ BK∗(νI0)−2⊂ e X5,3and Lemma 4.2, we ha e ha kp−2 h(2∂uL+ ou +∂uΨ)k0,0≤ kp−2 hk−2,−2k2∂uL+ ou +∂uΨk2,2 ≤K2νI0 κk∂uL+ ou k5,3+(νI0)2 κ2k∂uΨk6,4≤K1 κ+K∗ κ2(4.16) o some cons an s Kindependen o νI0and κ. Then, using again Lemma 4.2, kF1k6,4=1 2kp−2 h(2∂uL+ ou +∂uΨ)∂uΨk6,4 ≤1 2kp−2 h(2∂uL+ ou +∂uΨ)k0,0k∂uΨk6,4 ≤K 21 κ+K∗ κ2K∗ (νI0)2. Now we deal wi h F2. We obse e ha , since kL+ ou k4,2=K(νI0)−1and Ψ∈ BK∗(νI0)−2⊂e X5,3, by Lemma 4.2, k2∂θL+ ou +∂θΨk0,0≤2K(νI0)2 κ2k∂θL+ ou k4,2+K(νI0)4 κ4k∂θΨk6,4≤KνI0 κ2+K∗νI0 κ4.(4.17) Then, kF2k6,4≤ν 2k2∂θL+ ou +∂θΨk0,0k∂θΨk6,4≤ν 2K1 + K∗ κ21 κ2(νI0)2. 19 Then, e F(Ψ) ∈ X6,4and, by Lemma (4.3), aking κla ge enough, Gu◦e F(Ψ) ∈ BK∗(νI0)−2⊂e X5,3. Now we check ha e Fis Lipschi z wi h Lip e F ≤ Kκ−1. Le Ψ,Ψ′∈ BK∗(νI0)−2⊂e X5,3. Obse e ha kp−2 h(2∂uL+ ou +∂uΨ + ∂uΨ′)k0,0and k2∂θL+ ou +∂θΨ + ∂θΨ′k0,0a e bounded as in (4.16) and (4.17). Then, ke F(Ψ) −e F(Ψ′)k6,4≤1 2kp−2 h(2∂uL+ ou +∂uΨ + ∂uΨ′)k0,0k∂uΨ−∂uΨ′k6,4 +νk2∂θL+ ou +∂θΨ + ∂θΨ′k0,0k∂θΨ−∂θΨ′k6,4 ≤K1 κ+2K∗ κ2TΨ−Ψ′U5,3+νK νI0 κ2+ 2K∗νI0 κ4(νI0)−1TΨ−Ψ′U5,3 ≤K κTΨ−Ψ′U5,3, o some cons an K2>0. Then, by he las claim o Lemma 4.3, TGu◦e F(Ψ) −Gu◦e F(Ψ′)U5,3≤Kke F(Ψ) −e F(Ψ′)k6,4≤K κTΨ−Ψ′U5,3. The claim ollows aking κla ge enough. Then, we easily check ha Gu◦e Fsends he ball BK∗(νI0)−2 in o i sel and has a unique ixed poin he e. 5 Fi s ex ension o he in a ian mani old In Sec ion 4we ha e ound he ex ension o he local uns able in a ian mani old o he complex domain D+ κ,δ ×Tσ(see Figu e 2) by means o he unc ion Φ+= Φ0+L+ ou + Φ+ 2, whe e Φ0is in oduced in (4.5), L+ ou in (4.14) and Φ+ 2in P oposi ion 4.5. Hence, as commen ed in Rema k 4.1, he pa ame iza ion o he s able mani old is gi en by Φ−(u, θ) = −Φ+(−u, −θ). I is de ined in D− κ,δ ×Tσ, whe e D− κ,δ =−D+ κ,δ. This ex ension o Φ+is no enough o ou pu poses, because D+ κ,δ ∩ D− κ,δ ∩R=∅and we canno compu e he di e ence be ween he mani olds in he eals. In his sec ion we will ex end Φ+ o a la ge domain, D+ κ,δ ∪D+ κ,ex , de ined below in (5.21) (see Figu e 3). Once ex ended, he pa ame iza ions o he uns able and s able mani olds will be de ined in a common domain con aining an in e al o R. We will compu e he di e ence o he mani olds in his common domain in Sec ion 9. We ema k ha we ha e no been able o ind he ex ension o Φ+in a single s ep because he Hamil on-Jacobi equa ion (4.3) is no de ined a u= 0. The eason lies in he ac ha he me hod we ha e used o ind Φ+ equi es compu ing some in eg als along s aigh lines wi h some slope in he complex domain whe e he a iable uli es. These s aigh lines canno go h ough 0and hence he cu en me hod does no allow us o ex end Φ+beyond u= 0 di ec ly. In his sec ion we will ind an ex ension o Φ+ o D+ κ,ex by choosing ano he ype o pa ame iza ion o he in a ian mani old, and hen we will go back o he o iginal ype o pa ame iza ion. Howe e , his ex ension will no be de ined a u= 0. 5.1 F om Hamil on-Jacobi pa ame iza ion o low pa ame iza ion Taking in o accoun (4.1) and (4.2), he solu ion Φ+= Φ0+L+ ou + Φ+ 2o he Hamil on-Jacobi equa ion (4.3) ob ained in Sec ion 4p o ides he pa ame iza ion o he uns able mani old     q p θ J    = Γ+(u, θ) =     qh(u) 1 ph(u)∂uΦ+(u, θ) θ ∂θΦ+(u, θ)    = Γ0(u, θ) + Γ1(u, θ) + Γ2(u, θ),(5.1) whe e Γ0(u, θ) =     qh(u) 1 ph(u)∂uΦ0(u) θ 0    ,Γ1(u, θ) =     0 1 ph(u)∂uL+ ou (u, θ) 0 ∂θL+ ou (u, θ)    (5.2) and Γ2= Γ+−Γ0−Γ1. We ecall ha ph(0) = 0. Howe e , Γ0is analy ic a u= 0 because ph(u)−1∂uΦ0(u) = ph(u). 20 Le X= (Xq, Xp, Xθ, XJ)⊤be he ec o ield co esponding o H, in (2.3), using he 2- o m in (2.1), and le φ be i s low. We look o a change o a iables (u, θ) = ( + 1( , ϕ), ϕ + 2( , ϕ)) such ha conjuga es Xon he uns able in a ian mani old, pa ame ized by e Γ+( , ϕ) = Γ+( + 1( , ϕ), ϕ + 2( , ϕ)) (5.3) o he ec o ield (1, νI0), ha is, φ (e Γ+( , ϕ)) = e Γ+( + , ϕ +νI0 ) o , equi alen ly, L(e Γ+) = X◦e Γ+,(5.4) whe e L(Γ) = ∂ Γ + νI0∂ϕΓis he ope a o de ined in (4.7). An immedia e compu a ion shows ha (5.3) sa is ies (5.4) i and only i = ( 1, 2)is a solu ion o [∂uΓ+◦(Id + )](1 + L( 1)) + [∂θΓ+◦(Id + )](νI0+L( 2)) = X◦Γ+◦(Id + ).(5.5) We emphasize ha he abo e equa ion has ou componen s. Howe e , he symplec ic cha ac e o he ec o ield Xensu es ha i wo o hem a e sa is ied, so a e he o he wo. We choose o sol e he equa ions co esponding o he i s and hi d componen s o (5.5). Taking in o accoun (5.1), he equali y ˙qh=−qhphand he ac ha ∂uΦ0=p2 h, we can w i e hese wo equa ions as L( ) = A◦(Id + ),(5.6) whe e A=A1 A2=p−2 h(∂uL+ ou +∂uΦ+ 2) ν(∂θL+ ou +∂θΦ+ 2).(5.7) We deno e N( ) he igh hand side o (5.6). We ha e ha N( ) = A+DA +R( ),(5.8) whe e DA deno es he de i a i e o Aand R( ) = A◦(Id + )−A−DA . We will see in a momen ha equa ion (5.6) canno be sol ed di ec ly as a ixed poin equa ion because he linea e m DA in (5.8) is oo la ge. We will need o ew i e i in a be e sui ed way. 5.1.1 P elimina ies and echnical lemmas o sol e equa ion (5.6) To sol e equa ion (5.6), we conside = ( 1, 2)∈ X ,s ×X +1,s+1, wi h he no m k k ,s =k 1k ,s +k 2k +1,s+1 and he ope a o Guin (4.13), ac ing on each componen . Also, gi en a ma ix unc ion M=M1,1M1,2 M2,1M2,2 wi h M1,1, M1,2∈ X ,s and M2,1, M2,2∈ X +1,s+1 we de ine kMk ,s = max {kM1,1k ,s +kM2,1k +1,s+1, νI0(kM1,2k ,s +kM2,2k +1,s+1)}.(5.9) I ollows immedia ely om Lemma 4.2 ha , i , s ∈Rand ˜ , ˜s≥0, kMk ,s ≤KνI0 κ˜s kMk +˜ ,s+˜s(5.10) and, o any , ′, s, s′∈R, kM k + ′,s+s′≤ kMk ,sk k ′,s′.(5.11) 21 Indeed, inequali y (5.10) ollows immedia ely om (1) o Lemma 4.2. As o (5.11), using (2) o Lemma 4.2, we ha e ha k(M )1k + ′,s+s′+k(M )2k + ′+1,s+s′+1 =kM1,1 1+M1,2 2k + ′,s+s′+kM2,1 1+M2,2 2k + ′+1,s+s′+1 ≤ kM1,1 1k + ′,s+s′+kM1,2 2k + ′,s+s′+kM2,1 1k + ′+1,s+s′+1 +kM2,2 2k + ′+1,s+s′+1 ≤(kM1,1k ,s +kM2,1k +1,s+1)k 1k ′,s′+KνI0 κ(kM1,2k ,s +kM2,2k +1,s+1)k 2k ′+1,s′+1 ≤ kMk ,sk k ′,s′, i κ≥K. We will look o he solu ion o equa ion (5.6) in a domain sligh ly smalle han D+ κ,δ ×Tσ. The no ms we use depend on he choice o he domains. In pa icula , hey depend on κ,δand σ. Below, we will inc ease κ o ˜κand dec ease δ o ˜ δ. In o de o ha e he dis ance om he poin s o he bounda y o D+ ˜κ,˜ δ o D+ κ,δ cons an , when aking ˜κ > κ we will ake δ−˜ δ=˜κ−κ νI0 cos β1 cos β2, some imes wi hou explici men ion o i . To cla i y he exposi ion, ill he end o he sec ion, we include σand κas subsc ip s in he no ms, bu no δ, since we will unde s and ha when changing he domain he p e ious ule applies. In his way k k ,s,κ,σ will deno e he no m k k ,s o de ined ei he in D+ κ,δ o in D+ κ,δ ×Tσ, depending on he se ing. We ema k ha i ˜κ > κ (wi h ˜κ(νI0)−1<˜ δ) and 0<˜σ < σ, hen D+ ˜κ,˜ δ×T˜σ⊂ D+ κ,δ ×Tσ. Analogously, we will deno e he spaces by X ,s,κ,σ o cla i y hei dependence on he domain. The educ ion o domain will only be done a ini e numbe o imes. Lemma 5.1. Fo all ˜κ > κ and 0<˜σ < σ, he e exis s C > 0such ha i B∈ X ,s,κ,σ, hen, o all m, n ∈N,∂m u∂n θB∈ X ,s,˜κ,˜σwi h k∂m uBk ,s,˜κ,˜σ≤C˜κ κs(νI0)mm! (˜κ−κ)m 1 (cos β1)mkBk ,s,κ,σ, m ≥0, k∂m u∂n θBk ,s,˜κ,˜σ≤C˜κ κs(νI0)mm!n! (˜κ−κ)m(σ−˜σ)n+1 1 (cos β1)mkBk ,s,κ,σ, m ≥0, n ≥1. When applying he p e ious lemma, we will choose ˜κ=κ+κ0, whe e κ0>0is ixed. In his way, ˜κ/κ = 1 + κ0/κ < 2, i κis la ge enough. P oo o Lemma 5.1.We no e ha (∂m u∂n θB)[k]= (ik)n∂m uB[k]. By Cauchy o mula, ∂m uB[k](u) = m! 2πi Zγu B[k](z) (z−u)m+1 dz, aking γu o be he ci cle o adius (˜κ−κ)(νI0)−1cos β1, we immedia ely ha e, o some C1>0, k∂m uB[k]k ,s,˜κ,˜σ≤C1˜κ κsm!(νI0)m (˜κ−κ)m 1 (cos β1)mkB[k]k ,s,κ,σ. Hence, since kB[k]k ,s,κ,σ ≤ kBk ,s,κ,σe−|k|σ, we ha e ha k∂m u∂n θB[k]k ,s,˜κ,˜σ≤C1˜κ κsm!|k|n(νI0)m (˜κ−κ)m 1 (cos β1)me−|k|σkBk ,s,κ,σ. The e o e, k∂m u∂n θBk ,s,˜κ,˜σ=X k∈Zk∂m u∂n θB[k]k ,s,˜κ,˜σe|k|˜σ ≤C1 (cos β1)m˜κ κsm!(νI0)m (˜κ−κ)mkBk ,s,κ,σ X k∈Z|k|ne−|k|(σ−˜σ) ≤C1C2 (cos β1)m˜κ κsm!n!(νI0)m (˜κ−κ)m(σ−˜σ)n+1 kBk ,s,κ,σ, whe e we ha e used ha Pk≥0kne−bk ≤C2n!/bn+1, o b > 0and n≥1, o some C2. 22 Lemma 5.2. Le Cbe he cons an gi en by Lemma 5.1 and ′≥0and s′>0. Gi en K > 0and δ > 0, o any 0<˜σ < σ, he e exis κ0>0such ha o any ˜κ > κ +δ > κ ≥κ0, i B∈ X ,s,κ,σ and ∈ X ′,s′,˜κ,˜σ×X ′+1,s′+1,˜κ,˜σwi h k k ′,s′,˜κ,˜σ≤K/(νI0)s′+1, hen B◦(Id + )∈ X ,s,˜κ,˜σand kB◦(Id + )k ,s,˜κ,˜σ≤2C σ−˜σ˜κ κs kBk ,s,κ,σ. P oo . Fi s o all, by (1) o Lemma 4.2, we ha e ha k 1k0,0,˜κ,˜σ≤K(νI0)s′ ˜κs′k 1k ′,s′,˜κ,˜σ≤K ˜κs′νI0 , k 2k0,0,˜κ,˜σ≤K(νI0)s′+1 ˜κs′+1 k 2k ′+1,s′+1,˜κ,˜σ≤K ˜κs′+1 . Then, expanding Bin Taylo se ies and using Lemma 5.1, we ha e ha , w i ing α1= cos β1, kB◦(Id + )k ,s,˜κ,˜σ≤X j≥0 1 j! j X ℓ=0 j ℓk∂j−ℓ u∂ℓ θB j−ℓ 1 ℓ 2k ,s,˜κ,˜σ ≤X j≥0 j X ℓ=0 1 (j−ℓ)!ℓ!k∂j−ℓ u∂ℓ θBk ,s,˜κ,˜σk 1kj−ℓ 0,0,˜κ,˜σk 2kℓ 0,0,˜κ,˜σ ≤C σ−˜σ˜κ κsX j≥0 j X ℓ=0 K ˜κs′νI0j−ℓK ˜κs′+1 ℓ(νI0)j−ℓ (α1(˜κ−κ))j−ℓ(σ−˜σ)ℓkBk ,s,κ,σ ≤C σ−˜σ˜κ κsX j≥0 Kj j X ℓ=0 1 (˜κs′(α1(˜κ−κ))j−ℓ 1 (˜κs′+1(σ−˜σ))ℓkBk ,s,κ,σ ≤C σ−˜σ˜κ κsX j≥0K1 ˜κs′α1(˜κ−κ)+1 ˜κs′+1(σ−˜σ)j kBk ,s,κ,σ ≤2C σ−˜σ˜κ κs kBk ,s,κ,σ, whe e we ha e chosen κ0such ha K ˜κs′1 α1(˜κ−κ)+1 ˜κ(σ−˜σ)≤1 2. 5.1.2 Solu ion o equa ion (5.6) Le Gube he ope a o de ined in (4.13). We o mally de ine 0=Gu(A), F0=Gu(DA).(5.12) Lemma 5.3. Le Abe he unc ion de ined in (5.7). Le ˜κ > κ and 0<˜σ < σ, wi h κbig. Then, he e exis s K > 0such ha (1) kAk3,1,κ,σ ≤K(νI0)−1, (2) k 0k3,1,κ,σ ≤K(νI0)−2, (3) kDAk3,1,˜κ,˜σ≤K, (4) kF0k3,1,˜κ,˜σ≤K(νI0)−1. P oo . We w i e A=A0+A1, whe e A0=p−2 h∂uL+ ou ν∂θL+ ou , A1=p−2 h∂uΦ+ 2 ν∂θΦ+ 2. 23 Taking in o accoun ha p−2 h∈ X−2,−2,κ,σ and he p ope ies o L+ ou in P oposi ion 4.4, we ha e ha kA0k3,1,κ,σ ≤K(νI0)−1and hA0i= 0. Also, by he p ope ies o Φ+ 2in P oposi ion 4.5, we ha e ha kA1k4,2,κ,σ ≤K(νI0)−2. Hence, kA1k3,1,κ,σ ≤Kκ−1(νI0)−1. This p o es (1). We bound kGu(A0)k3,1,κ,σ and kGu(A1)k3,1,κ,σ sepa a ely. Since hA0i= 0, by (1) o Lemma 4.3, kGu(A0)k3,1,κ,σ ≤K νI0kA0k3,1,κ,σ ≤K (νI0)2. Using again ha p−2 h∈ X−2,−2, he p ope ies o Φ+ 2in P oposi ion 4.5 imply ha kA1k4,2,κ,σ ≤ K(νI0)−2. Then, by (2) o Lemma 4.3, kGu(A1)k3,1,κ,σ ≤KkA1k4,2,κ,σ ≤K (νI0)2, om which (2) ollows. We w i e DA =DA0+DA1. F om he p e ious bounds o A0and A1, applying Lemma 5.1 and he de ini ion o he ma ix no m (5.9), we ha e ha , in he educed domain, kDA0k3,1,˜κ,˜σ≤K, kDA1k4,2,˜κ,˜σ≤K κνI0 . He e he cons an s depend on ˜κ−κand σ−˜σ. This p o es (3). We inally p o e (4). Since hA0i= 0, we ha e ha hDA0i= 0. By (1) o Lemma 4.3, kGu(DA0)k3,1,˜κ,˜σ≤K νI0 . Mo eo e , by (2) o Lemma 4.3, kGu(DA1)k3,1,˜κ,˜σ≤KkDA1k4,2,˜κ,˜σ≤K νI0 . Since F0=Gu(DA0) + Gu(DA1), he claim ollows. We in oduce ˜ by = 0+ (Id + F0)˜ . Obse e ha , by (4) o Lemma 5.3 and (1) o Lemma 4.2, kF0k0,0,˜κ,˜σ≤KνI0 κkF0k3,1,˜κ,˜σ≤K κ. Hence, i κis la ge enough, Id+F0is in e ible and k(Id+F0)−1k0,0,κ,σ ≤2. Using ha , by (5.12), L( 0) = Aand L(F0) = DA, we ew i e equa ion (5.6) as L(˜ ) = e N(˜ ),(5.13) whe e e N(˜ ) = (Id + F0)−1DA 0+ (Id + F0)−1DA F0˜ + (Id + F0)−1R 0+ (Id + F0)˜  and Rwas in oduced in (5.8). Using he ope a o Gu, we ew i e equa ion (5.13) as he ixed poin equa ion ˜ =Gu◦e N(˜ ).(5.14) P oposi ion 5.4. Fo all ˆκ > ˜κ > κ and 0<ˆσ < ˜σ < σ, wi h κbig enough, equa ion (5.14)has a solu ion ˜ +, de ined in D+ ˆκ,ˆ δ×Tˆσ, and ˜ +∈ X3,1,ˆκ,ˆσ× X4,2,ˆκ,ˆσwi h k˜ +k3,1,ˆκ,ˆσ≤C(νI0)−2. Consequen ly, e Γ+= Γ+◦(Id+ 0+(I+F0)˜ +)sa is ies he in a iance equa ion (5.4)in D+ ˆκ,δ ×Tˆσ. 24 P oo o P oposi ion 5.4.We claim ha he e exis s K1>0such ha kGu◦e N(0)k3,1,ˆκ,ˆσ≤K1 (νI0)2. Indeed, i s we no ice ha e N(0) = (Id+F0)−1(DA 0+R( 0)) = (Id+F0)−1DA 0+Z1 0 (1 −s)D2A◦(Id + s 0)ds ( 0)⊗2 = (Id + F0)−1DA 0+Z1 0 (1 −s) 0 1∂uDA ◦(Id + s 0) 0+ 0 2∂θDA ◦(Id + s 0) 0ds. Nex , we no e ha kDA 0k4,2,ˆκ,ˆσ≤ kDA 0k6,2,ˆκ,ˆσ≤ kDAk3,1,ˆκ,ˆσk 0k3,1,ˆκ,ˆσ≤K (νI0)2. By (3) o Lemma 5.3 and Lemma 5.1, o ˆκ > ˜κand 0<ˆσ < ˜σ, we ha e k∂uDAk3,1,ˆκ,ˆσ≤KνI0kDAk3,1,˜κ,˜σ≤KνI0, k∂θDAk3,1,ˆκ,ˆσ≤KkDAk3,1,˜κ,˜σ≤K. (5.15) Mo eo e , by (1) o Lemma 4.2 and (2) o Lemma 5.3, k 0 1∂uDA ◦(Id + s 0) 0k4,2,ˆκ,ˆσ≤KνI0 κk 0 1∂uDA ◦(Id + s 0) 0k9,3,ˆκ,ˆσ≤K κ(νI0)2 and, since 0 2∈ X4,2,ˆκ,ˆσ, k 0 2∂θDA ◦(Id + s 0) 0k4,2,ˆκ,ˆσ≤KνI0 κ2 k 0 2∂ DA ◦(Id + s 0) 0k10,4,ˆκ,ˆσ≤K κ2(νI0)2. Hence, kGu◦e N(0)k3,1,ˆκ,ˆσ≤Kke N(0)k4,2,ˆκ,ˆσ≤K1 κ(νI0)2. Le C= 2K1. Le , ′∈ X3,1,ˆκ,ˆσ×X4,2,ˆκ,ˆσwi h k k3,1,ˆκ,ˆσ,k ′k3,1,ˆκ,ˆσ≤e C. We ha e ha e N( )−e N( ′) = (I+F0)−1(M1+M2) ( − ′),(5.16) whe e M1=DA F0, M2( , ′) = Z1 0Z1 0 D2A◦(Id + us( , ′)) d us( , ′)ds (I+F0) wi h us( , ′) = 0+ (Id + F0) ′+s(I+F0)( − ′). Then, using (1) o Lemma 4.2 and (3) and (4) o Lemma 5.3, we ha e ha kM1k1,1,ˆκ,ˆσ≤KνI0 κkDAF 0k6,2,ˆκ,ˆσ≤KνI0 κkDAk3,1,ˆκ,ˆσkF0k3,1,ˆκ,ˆσ≤K κ.(5.17) Obse e ha , by (2) o Lemma 5.3 and he hypo heses on , ′, kus( , ′)k3,1,ˆκ,ˆσ≤K(νI0)−2. Hence, also using (5.15) kus,1∂uDA ◦(Id + us)k1,1,ˆκ,ˆσ≤KνI0 κkus,1∂uDA ◦(Id + us)k6,2,ˆκ,ˆσ ≤KνI0 κkus,1k3,1,ˆκ,ˆσk∂uDA ◦(Id + us)k3,1,ˆκ,ˆσ≤K κ 25 whe e Lin(T2) = ∂ T2+∂θT2, Fin(T2) = −ν 2(∂θL+ in)2+ 2 2(∂ L+ in)2+ν∂θL+ in∂θT2+ν 2(∂θT2)2+ 4 2∂ L+ in∂ T2+ 2 2(∂ T2)2, whe e we ha e used ha Lin(L+ in) = −E(T0). 6.1 Spaces and echnical lemmas To deal wi h equa ion (6.9) we ha e o in oduce some unc ion spaces and p o ide basic p ope ies o he ope a o Lin. We conside he domain D+ κ,in ={ ∈C| ℑ < −( an β1)ℜ −κ}∪{ ∈C| ℑ > ( an β1)ℜ +κ},(6.10) wi h κ > 1. See Figu e 5. We no ice ha he image o D+ κ,δ ∪ D+ κ,ex by he ans o ma ion u=i+ (νI0)−1 is con ained in D+ κ,in. Figu e 5: The domain D+ κ,in de ined in (6.10), shaded in g ay. To sol e equa ion (6.9), o ∈R, we in oduce he Banach space o 2π-pe iodic in θ, analy ic unc ions Y ={R:D+ κ,in ×Tσ→C| kRk <∞},(6.11) whe e, aking in o accoun he Fou ie expansion o R( , θ) = Pk∈ZR[k]( )eikθ , kRk =X k∈ZkR[k]k e|k|σ,(6.12) and, o an analy ic unc ion :D+ κ,in →C, k k = sup ∈D+ κ,in | ( )|. Lemma 6.1. Le , 1, 2∈R. (1) I R∈ Y +s,s≥0, hen R∈ Y and he e exis s K > 0such ha kRk ≤K1 κskRk +s. 32 (2) I R1∈ Y 1and R2∈ Y 2, hen R1R2∈ Y 1+ 2and kR1R2k 1+ 2≤ kR1k 1kR2k 2. We also in oduce he Banach space e Y ={R∈ Y |∂ R, ∂θR∈ X +1,TRU <∞},(6.13) wi h he no m TRU =kRk +k∂ Rk +1 +k∂θRk +1.(6.14) We will use he nex echnical lemma se e al imes. I is analogous o Lemma 4.3. Lemma 6.2. Le Gu in be he ope a o de ined in (6.7). The e exis s K > 0such ha (1) I R∈ Y wi h > 0and hRi= 0, hen Gu in(R)∈ Y and kGu in(R)k ≤KkRk . (2) I R∈ Y wi h > 1, hen Gu in(R)∈ Y −1and kGu in(R)k −1≤KkRk . (3) I R∈ Y wi h > 0, hen ∂ Gu in(R), ∂θGu in(R)∈ Y and k∂ Gu in(R)k ≤KkRk ,k∂θGu in(R)k ≤KkRk . As a consequence, i R∈ Y , wi h > 1,Gu in(R)∈e Y −1and TGu in(R)U −1≤KkRk . The cons an Konly depends on and he cons an s in ol ed in he de ini ion o D+ κ,in. 6.2 Fixed poin equa ion We conside he equa ion T2=Gu in ◦Fin(T2).(6.15) We decompose Fin(T2) = −(F0+F1+F2+F3+F4),(6.16) wi h F0( , θ) = ν 2(∂θL+ in( , θ))2+ 2 2(∂ L+ in( , θ))2, F1( , θ) = ν∂θL+ in( , θ)∂θT2( , θ), F2( , θ) = ν 2(∂θT2( , θ))2, F3( , θ) = 4 2∂ L+ in( , θ)∂ T2( , θ), F4( , θ) = 2 2(∂ T2( , θ))2. I T2is a solu ion o he ixed poin equa ion (6.15) i is also a solu ion o (6.9). In iew o (6.8), since V[0] = 0, we ha e ha (L+ in)[0] = 0. The ollowing p oposi ion is analogous o P oposi ion 4.4. I s p oo ollows exac ly he same lines. P oposi ion 6.3. We ha e L+ in, ∂θL+ in ∈ Y2and ∂ L+ in ∈ Y3. Mo eo e , he e exis s K > 0, independen o κ, such ha kL+ ink2,k∂θL+ ink2,k∂ L+ ink3≤K. Mo i a ed by P oposi ion 6.3, we in oduce he cons an ΘV=kL+ ink2 2+k∂θL+ ink2 2+k∂ L+ ink2 31/2.(6.17) Rema k 6.4. I one eplaces iby ε˜ iin he de ini ion o Vin (1.2), hen ΘV=O(ε). 33 P oposi ion 6.5. The e exis K1>0and κ0such ha , i κ > κ0, he ope a o Gu in ◦Fin :BK1Θ2 V⊂ e Y3→ BK1Θ2 Vis well de ined and a con ac ion. Hence, equa ion (6.15)has a solu ion T+ 2∈e Y3 sa is ying TT+ 2U3≤K1Θ2 V.(6.18) P oo . We s a by bounding F0. By P oposi ion 6.3, kF0k4≤ν 2(∂θL+ in)24+ 2k 2(∂ L+ in)2k4≤ν 2k∂θL+ ink2 2+ 2k 2k−2k∂ L+ ink2 3< K2Θ2 V,(6.19) o some K2>0. We ake K1= 2kGu inkK2and K∗=K1Θ2 V. In his p oo kGu inks ands o he ope a o no m o Gu in :Y4→e Y3. Le T2∈ BK∗⊂e Y3. We claim ha Fin(T2)∈ Y4and kFin(T2)k4≤ kF0k4+Kνk∂θL+ ink2 κ2+KνK∗ 2κ4+K4k∂ L+ ink3 κ+K2K∗ κ2K∗.(6.20) Indeed, nex we deal wi h Fj,j= 1,...,4. By P oposi ion 6.3 and Lemma 6.1 kF1k4=kν∂θL+ in∂θT2k4=νk∂θL+ ink0k∂θT2k4≤Kνk∂θL+ ink2 κ2TT2U3≤Kνk∂θL+ ink2K∗ κ2, since k∂θT2k4≤TT2U3≤K∗. Again by Lemma 6.1, kF2k4=ν 2(∂θT2( , θ))24≤ν 2k∂θT2k0k∂θT2k4≤Kν 2κ4k∂θT2k4k∂θT2k4≤Kν(K∗)2 2κ4. Now, by P oposi ion 6.3, Lemma 6.1 and he ac ha k∂ T2k4≤TT2U3≤K∗, kF3k4=4 2∂ L+ in∂ T24≤4 2k−2k∂ L+ ink2k∂ T24≤K4k∂ L+ ink3 κK∗. Finally, kF4k4=2 2(∂ T2( , θ))24≤2 2∂ T2( , θ)0k∂ T2( , θ)k4 ≤ k2 2k−2k∂ T2( , θ)k2k∂ T2( , θ)k4≤K2 κ2k∂ T2( , θ)k4k∂ T2( , θ)k4≤K2(K∗)2 κ2. This p o es (6.20). Now we choose κ0>1such ha Kνk∂θL+ ink2 κ2 0 +νK∗ 2κ4 0 +4k∂ L+ ink3 κ0 +2K∗ κ2 0K∗< K2Θ2 V. Hence, o any κ > κ0, i T2∈ BK∗, by he las claim o Lemma 6.2, TGu in ◦Fin(T2)U3≤ kGu inkkFin(T2)k4≤2kGu inkK2Θ2 V=K∗. Nex we check ha Gu in ◦Fin is a con ac ion on BK∗. We claim ha he e exis s K3>0such ha , i T2, T ′ 2∈ BK∗, kFin(T2)−Fin(T′ 2)k4≤K3 κTT2−T′ 2U3.(6.21) To p o e his claim, we w i e Fin(T2)−Fin(T′ 2) = − 4 X i=1 (Fi(T2)−Fi(T′ 2)) , whe e F1(R) = ν∂θL+ in∂θR, F2(R) = 1 2ν(∂θR)2, F3(R)( , θ) = 4 2∂ L+ in( , θ)∂ R( , θ), F4(R)( , θ) = 2 2(∂ R( , θ))2. 34 We bound each di e ence sepa a ely. Fi s , by P oposi ion 6.3 and Lemma 6.1, we ha e ha kF1(T2)−F1(T′ 2)k4≤ kν∂θL+ ink0k∂θT2−∂θT′ 2k4≤Kνk∂θL+ ink2 κ2TT2−T′ 2U3. Second, kF2(T2)−F2(T′ 2)k4=ν 2k(∂θT2+∂θT′ 2)(∂θT2−∂θT′ 2)k4 ≤ν 2k(∂θT2+∂θT′ 2)k0k∂θT2−∂θT′ 2k4 ≤Kν 2 1 κ4k∂θT2+∂θT′ 2k4k∂θT2−∂θT′ 2k4 ≤KK∗ν κ4TT2−T′ 2U3. Thi d, using again P oposi ion 6.3 and Lemma 6.1, kF3(T2)−F3(T′ 2)k4≤4 2∂ L+ in0k∂ T2−∂ T′ 2k4≤4∂ L+ in3 κTT2−T′ 2U3. And ou h, kF4(T2)−F4(T′ 2)k4≤ k2 2(∂ T2+∂ T′ 2)k0k∂ T2−∂ T′ 2k4 ≤ k2 2k−2k∂ T2+∂ T′ 2k2k∂ T2−∂ T′ 2k4 ≤K2 κ2k∂ T2+∂ T′ 2k4k∂ T2−∂ T′ 2k4 ≤4KK∗ κ2TT2−T′ 2U3. Inequali y (6.21) ollows om combining hese ou s eps, since κ > κ0>1and κ0is big. Finally, we check ha he ope a o Gu in ◦Fin is a con ac ion in BK∗. Indeed, i T2, T ′ 2∈ BK∗, using he las s a emen o Lemma 6.2 and (6.21), TGu in ◦Fin(T2)−Gu in ◦Fin(T′ 2)U3≤ kGu inkkFin(T2)−Fin(T′ 2)k4≤ kGu inkK3 κTT2−T′ 2U3. Hence, by he s anda d a gumen , aking κ0la ge enough, Gu in ◦Fin sends BK∗in o i sel and has a unique ixed poin T+ 2in his ball. The bound (6.18) ollows om he de ini ion o K∗. Co olla y 6.6. The inne equa ion (6.2)admi s a solu ion T+=T0+L+ in +T+ 2, whe e T0is gi en by (6.3),L+ in is de ined in (6.8)and T+ 2is gi en by P oposi ion 6.5. 7 App oxima ion o he mani old in he inne domain Le T+=T0+L+ in +T+ 2be he solu ion o he inne equa ion (6.2) in he domain D+ κ,in gi en by Co olla y 6.6. F om P oposi ion 4.5, we ha e ha he solu ion Φ+(u, θ)o he Hamil on-Jacobi equa ion (4.3) and i s ex ension o he domain D+ κ,δ ∪D+ κ,ex B∗ ρ(whe e B∗ ρis a ixed small ball cen e ed a he o igin), wi h anishing con ou condi ions a ℜu=−∞, is gi en by Φ+= Φ0+L+ ou + Φ+ 2, whe e Φ0was in oduced in (4.5), L+ ou in (4.14) and Φ+ 2∈e X5,3, hence Φ+ 2(u, θ)∼(νI0)−2 (u−i)3. The app oxima ion o Φ+by Φ0+L+ ou is no good enough i u−i∼(νI0)−1, al hough P opo- si ion 5.8 ensu es ha he mani olds can be ex ended o D+ κ,δ ∪ D+ κ,ex B∗ ρ. In o de o ob- ain a be e app oxima ion o Φ+, we compa e i wi h he solu ion o he inne equa ion (6.2), T+=T0+L+ in +T+ 2, gi en by Co olla y 6.6. 35 We ecall ha he unc ion S+( , θ) = (νI0)−1Φ+(i+ (νI0)−1 , θ) is a solu ion o he Hamil on-Jacobi equa ion (6.1) in he ans o med domain. Ac ually, we wan o compa e S+wi h he solu ion T+o he inne equa ion. Bo h unc ions a e al eady de e mined. We w i e S+=T0+L+ in +T+ 2+S+ 2 and de i e bounds and p ope ies o S+ 2 om he equa ion i sa is ies. Using ha T+=T0+L+ in +T+ 2is a solu ion o he inne equa ion (6.2), we ha e ha S+ 2is a solu ion o Lin(S2) = b Fin,a(S2),(7.1) whe e Lin(S2) = ∂ S2+∂θS2was de ined in (6.6) and b Fin,a(S2) = −e E+ν∂θT+∂θS2+1 2ν(∂θS2)2+ (2A1∂ T+−1)∂ S2+A1(∂ S2)2(7.2) wi h A1( ) = 1 2 2(2i+ (νI0)−1 )2 (i+ (νI0)−1 )2, A2( , θ) = −1 2 (i+ (νI0)−1 )2 2(2i+ (νI0)−1 )2+1 2 1 2(2i+ (νI0)−1 )2V(θ), e E( , θ) = (A1( )−2 2)(∂ T+ 0)2+A2( , θ) + 1 8 2+1 8 2V(θ). (7.3) Le β1>0be he angle in ol ed in he de ini ion o D+ κ,δ (see (4.12)). Fix β3and β4sa is ying 0< β3< β4< β1. Fo α∈(0,1) and κ > 1, we de ine he domain D+ κ,α ={ ∈C| −(νI0)α− an β4ℜ < ℑ < min{−κ− an β1ℜu, −κ− an β3ℜu}}.(7.4) See Figu e 6. Obse e ha d(D+ κ,α,0) = κcos β3and | | ≤ K(νI0)α o ∈ D+ κ,α. Figu e 6: The domain D+ κ,α de ined in (7.4), shaded in g ay. 36 In o de o sol e equa ion (7.1), we conside he ollowing igh in e ses, b Guand b Gu s, o Lin. Fi s , b Guis de e mined by he exp ession o he Fou ie coe icien s o he image b Gu(S2): b Gu(S2)[k]( ) = Z + 0 eik( − )S[k] 2( )d i k≥0, b Gu(S2)[k]( ) = Z − 0 eik( − )S[k] 2( )d i k < 0, (7.5) whe e − 0=(νI0)α−κ an β1− an β4 +− an β4 an β1− an β4 + 1(νI0)α+ an β4 an β1− an β4 κi, + 0=−(νI0)α+κ an β4− an β3 + an β4 an β4− an β3−1(νI0)α− an β4 an β4− an β3 κi, wi h α∈(0,1) and 0< β3< β4< β1< π. See Figu e 6. The mos gene al igh in e se o Lin has he o m b Gu s(S2) = S2,0+b Gu(S2),(7.6) wi h S2,0∈ke Lin. Wi h his ope a o we conside he ixed poin equa ion S2=b Gu s◦b Fin,a(S2)(7.7) and we choose S2,0so ha he solu ion S+ 2o (7.7) is he analy ical con inua ion o S+−T0− L+ in −T+ 2 o he domain D+ κ,α. No e again ha i S+ 2is a ixed poin o b Gu s◦b Fin,a, i is also a solu ion o (7.1). Since S2,0∈ke Lin, S2,0( , θ) = X k∈Z S[k] 2,0( )eikθ =X k∈Z g[k]eik(θ− ), which de ines he coe icien s g[k]. I , mo eo e , S2is a solu ion o (7.7), we ha e S2( , θ) = S2,0( , θ) + b Gu◦b Fin,a(S2)( , θ). Fo k≥0, he Fou ie coe icien s sa is y S[k] 2( ) = S[k] 2,0( ) + Z + 0 eik( − )(b Fin,a(S2))[k]( )d and, aking in o accoun ha , a he poin s ( + 0, θ)o he bounda y, S2( , θ) = S+( , θ)−T0( , θ)−L+ in( , θ)−T+ 2( , θ), e alua ing a = + 0, we ge g[k]=S[k] 2,0( + 0)eik + 0= (S+−T0−L+ in −T+ 2)[k]( + 0)eik + 0 and inally, S[k] 2,0( ) = g[k]e−ik = (S+−T0−L+ in −T+ 2)[k]( + 0)e−ik( − + 0).(7.8) Analogously, we ob ain ha o k < 0 S[k] 2,0( ) = g[k]e−ik = (S+−T0−L+ in −T+ 2)[k]( − 0)e−ik( − − 0).(7.9) The e o e, we choose S2,0( , θ) = X k∈Z S[k] 2,0( )eikθ (7.10) wi h he coe icien s (7.8) and (7.9). 37 7.1 Spaces and echnical lemmas To sol e equa ion (7.7), o ∈R, we in oduce he Banach space o analy ic, 2π-pe iodic in θ unc ions Z ={R:D+ κ,α ×Tσ→C| kRk <∞}, wi h he no m k·k de ined as ollows. Using ha R( , θ) = Pk∈ZR[k]( )eikθ, kRk =X k∈ZkR[k]k e|k|σ, whe e, o an analy ic unc ion :D+ κ,α →C, k k = sup ∈D+ κ,α | ( )|. The ollowing lemma is e y simila o Lemma 6.1. Lemma 7.1. Le , 1, 2∈R. The e exis s K > 0such ha he ollowing holds. (1) I R∈ Z +swi h s≥0, hen R∈ Z and kRk ≤K1 κskRk +s. (2) I R1∈ Z 1and R2∈ Z 2, hen R1R2∈ Z 1+ 2and kR1R2k 1+ 2≤ kR1k 1kR2k 2. We also in oduce e Z ={R∈ Z |∂ R, ∂θR∈ Z +1,TRU <∞}, wi h he no m TRU =kRk +k∂ Rk +1 +k∂θRk +1. The ollowing esul is comple ely analogous o Lemma 6.2. The only di e ence is he domain o he unc ions o he space. Lemma 7.2. Le b Gube he ope a o de ined in (7.5). The e exis s K > 0such ha (1) I R∈ Z , wi h > 0, and R[0] = 0, kb Gu(R)k ≤KkRk . (2) I R∈ Z wi h > 1,b Gu(R)∈ Z −1and kb Gu(R)k −1≤KkRk . (3) I R∈ Z wi h > 0, hen ∂ b Gu(R), ∂θb Gu(R)∈ Z and k∂ b Gu(R)k ≤KkRk ,k∂θb Gu(R)k ≤KkRk , As a consequence, i R∈ Z , wi h > 1,b Gu(R)∈e Z −1and Tb Gu(R)U −1≤KkRk . The cons an Konly depends on and he cons an s in ol ed in he de ini ion o D+ κ,α. 38 7.2 The ixed poin equa ion Be o e sol ing he ixed poin equa ion (7.7) we deal wi h some p elimina y es ima es. Lemma 7.3. Le A1and e Ebe he unc ions in oduced in (7.3). The e exis s K > 0such ha , in D+ κ,α, we ha e (1) e E ∈ Z2wi h ke Ek2≤K(νI0)α−1. (2) A1∈ Z−2wi h kA1k−2≤K. (3) 2A1∂ T+−1∈ Z0wi h k2A1∂ T+−1k0≤K(νI0)α−1+Kκ−1. (4) ∂θT+∈ Z2wi h k∂θT+k2≤K. P oo . We ecall ha in he domain D+ κ,α,K1κ < | |< K2(νI0)α, o some K1, K2>0. We s a by p o ing (1). We ha e ha A1( )−2 2=1 2 2(2i+ (νI0)−1 )2 (i+ (νI0)−1 )2−2 2= 2 2(νI0)−1 (i+3 4(νI0)−1 ) (1 −i(νI0)−1 )2,(7.11) which implies ha kA1( )−2 2k−2≤K(νI0)α−1. Recall ha 0< α < 1. We claim ha he e exis s a cons an Ksuch ha k∂ T+k2≤K. Indeed, since T+=T0+L+ in+ T+ 2, by P oposi ions 6.3 and 6.5,k∂ L+ ink3≤Kand TT+ 2U3≤K. Hence, by (1) o Lemma 7.1, k∂ L+ ink2≤Kκ−1and k∂ T+ 2k2≤Kκ−2. Since ∂ T0= 1/(4 2), he claim ollows immedia ely om he p e ious bounds. Then, by (2) o Lemma 7.1, (A1( )−2 2)(∂ T+)22≤ kA1( )−2 2k−2k∂ T+k2 2≤K3(νI0)α−1. By he de ini ion o A2in (7.3), we ha e ha A2( , θ) + 1 8 2+1 8 2V(θ) = −1 2 (i+ (νI0)−1 )2 2(2i+ (νI0)−1 )2+1 8 2+1 2 1 2(2i+ (νI0)−1 )2+1 8 2V(θ) =1 2O((νI0)−1 ) which implies A2( , θ) + 1 8 2+1 8 2V(θ)2≤K(νI0)α−1. Hence, (1) ollows. (2) is an immedia e consequence o (7.11). Now we deal wi h (3). We ha e ha 2A1∂ T+−1 = 2A1∂ T0−1+2A1∂ (L+ in +T+ 2) = −1 4 (νI0)−1 (4i+ 3(νI0)−1 ) (i+ (νI0)−1 )2+2A1∂ (L+ in +T+ 2) which implies ha k2A1∂ T+−1k0≤ k2A1∂ T0−1k0+k2A1∂ (L+ in +T+ 2)k0 ≤K(νI0)α−1+k2A1k−2k∂ (L+ in +T+ 2)k2 ≤K(νI0)α−1+K κk∂ (L+ in +T+ 2)k3. (4) Follows di ec ly om P oposi ions 6.3 and 6.5. P oposi ion 7.4. The unc ion S2,0de ined in (7.10)sa is ies S2,0∈ Z0and kS[k] 2,0k1≤Kmax{(νI0)−2α,(νI0)−1+αlog(νI0)}e−|k|σ, k 6= 0. Consequen ly, in D+ κ,α ×Tσ′wi h 0< σ′< σ, kS2,0k1≤Kmax{(νI0)−2α,(νI0)−1+αlog(νI0)}. 39 P oo . We ha e ha (S+−T0−L+ in −T+ 2)( , θ) = (νI0)−1Φ0(i+ (νI0)−1 )−T0( ) + (νI0)−1L+ ou (i+ (νI0)−1 , θ)−L+ in( , θ) + (νI0)−1Φ+ 2(i+ (νI0)−1 , θ)−T+ 2( , θ), whe e Φ0was in oduced in (4.5), T0in (6.3), L+ ou in (4.14), L+ in in (6.8), Φ+ 2in P oposi ion 4.5 and T+ 2in P oposi ion 6.5. Fi s , an explici compu a ion shows ha , in he domain unde conside a ion, (νI0)−1Φ0(i+ (νI0)−1 )−T0( ) = i 4(νI0)−1log((νI0)−1 ) + (νI0)−1O((νI0)−1 ). Nex , also an explici compu a ion shows ha (νI0)−1(L+ ou )[k](i+ (νI0)−1 )−(L+ in)[k]( ) = −V[k]Z −∞ 4(νI0)−1i+ (νI0)−2s 8s(2 −(νI0)−1is)2eik(s− )ds =O(νI0)−1 (1 + O((νI0)−1 ))V[k]. Mo eo e , since Φ+ 2∈e X5,3wi h kΦ+ 2k5,3≤K(νI0)−2, |(νI0)−1(Φ+ 2)[k](i+ (νI0)−1 )| ≤ K| |−3e−|k|σ. Finally, since, by P oposi ion 6.5,T+ 2∈e Y3wi h kT+ 2k3≤K, |(T+ 2)[k]( )| ≤ K| |−3e−|k|σ. Since | ± 0|=O((νI0)α), he bounds o he Fou ie coe icien s ollow. To ge he bound in he k·k1 no m we ha e o es ic he domain o D+ κ,α ×Tσ′wi h 0< σ′< σ < σ0, whe e σ0was in oduced in (2.9). We conside he ixed poin equa ion S2=b Gu s◦b Fin,a(S2),(7.12) whe e b Gu sand b Fin,a we e de ined in (7.6) and (7.2), espec i ely. P oposi ion 7.5. Le α∈(0,1). Then, equa ion (7.12)has a solu ion S+ 2∈e Z1in D+ κ,α ×Tσ′ wi h kS+ 2k1≤K(νI0)−2α+K(νI0)−1+αlog(νI0). P oo . We i s check ha he e exis s K∗>0such ha BK∗⊂e Z1sa is ies b Gu s◦b Fin,a(BK∗)⊂ BK∗. To do so, gi en S2∈ BK∗, we w i e b Fin,a(S2) = F0+F1+F2+F3+F4, wi h F0=e E, F1=ν∂θT+∂θS2, F2=1 2ν(∂θS2)2, F3= (2A1∂ T+−1)∂ S2, F4=A1(∂ S2)2, whe e e E,A1and A2we e in oduced in (7.3). We claim ha Fi∈ Z2,i= 0,...,4, and he e exis s K > 0such ha kF0k2≤K(νI0)α−1,(7.13) kF1k2≤Kκ−2K∗,(7.14) kF2k2≤Kκ−2(K∗)2,(7.15) kF3k2≤K(νI0)α−1+κ−1K∗,(7.16) kF4k2≤K(K∗)2.(7.17) 40 Bound (7.13) is simply (1) o Lemma 7.3. Since k∂θT+k2≤K, by (1) o Lemma 7.1, we ha e ha kν∂θT+∂θS2k2≤νk∂θT+k1k∂θS2k1≤ν κ2k∂θT+k2k∂θS2k2≤Kκ−2K∗, which p o es (7.14). Bound (7.15) ollows analogously om  1 2ν(∂θS2)22≤ν 2k∂θS2k0k∂θS2k2≤ν 2 1 κ2(K∗)2. By (3) o Lemma 7.3, bound (7.16) ollows om k(2A1∂ T+−1)∂ S2k2≤ k2A1∂ T+−1k0k∂ S2k2≤K(νI0)α−1+κ−1K∗. Bound (7.17) ollows om (2) o Lemma 7.3 and kA1(∂ S2)2k2≤ kA1k−2k∂ S2k2 2≤K(K∗)2. In pa icula , om (7.13), P oposi ion 7.4 and he las claim o Lemma 7.2, since b Fin,a(0) = F0, we deduce ha Tb Gu s◦b Fin,a(0)U1=TS2,0+b Gu◦b Fin,a(0)U1≤TS2,0U1+Tb Gu◦b Fin,a(0)U1 ≤Kmax{(νI0)−2α,(νI0)−1+αlog(νI0)}+KkF0k2≤K1max{(νI0)−2α,(νI0)−1+αlog(νI0)}, o some K1>0. By he las claim o Lemma 7.2, he same ype o compu a ions imply ha , i S2, S′ 2∈ BK∗, Tb Gu s◦b Fin,a(S2)−b Gu s◦b Fin,a(S′ 2)U1≤Kkb Fin,a(S2)−b Fin,a(S′ 2)k2 ≤Kκ−1+ (νI0)α−1+K∗TS2−S′ 2U1. Then, aking K∗= 2Tb Gu s◦b Fin,a(0)U1= 2K1max{(νI0)−2α,(νI0)−1+αlog(νI0)}, he claim ollows wi h he usual a gumen , aking κand νI0la ge enough so ha Kκ−1+ (νI0)α−1+K∗<1/2. 8 Di e ence be ween solu ions o he inne equa ion In his sec ion we compu e he di e ence be ween he unc ions T±=T0+L± in +T± 2, wi h T+is gi en in D+ κ,in ×Tσwhe e D+ κ,in is de ined in (6.10) and T0( ) = −1/(4 )is in oduced in (6.3), L+ in is de ined in (6.8) and T+ 2is gi en by P oposi ion 6.5. Mo eo e , he unc ion T−is de ined by T−( , θ) = −T+(−¯ , −¯ θ) = T0( )−L+ in(−¯ , −¯ θ)−T+ 2(−¯ , −¯ θ)(8.1) in he domain (−D+ κ,in)×Tσ. We also de ine L− in( , θ) = −L+ in(−¯ , −¯ θ)and T− 2( , θ) = −T+ 2(−¯ , −¯ θ).(8.2) The ollowing lemma is an immedia e compu a ion. I ollows om he ac ha V es ic ed o Ris an e en unc ion, i.e. only depends on cosinus. We ecall ha E(T0)( , θ) = −V(θ)/8 2. Lemma 8.1. We ha e ha L− in( , θ) = Z∞ E(T0)(s, θ +s− )ds =−X k∈Z V[k] 8eik(θ− )Z∞ 1 s2eiks ds. I sa is ies he analogous bounds o L+ in in P oposi ion 6.3. 41 Figu e 8: The domain Dκde ined in (9.3), shaded in g ay. Compa e wi h Figu e 4. 9.1 S aigh ening he linea ope a o Since Φ±a e solu ions o (4.3), e ∆ou sa is ies e Le ∆ou = 0,(9.6) whe e e Le ∆ = 1 + B 1 + A∂ue ∆ + νI0∂θe ∆ and A=ν 2νI0∂θΦ++∂θΦ−, B=1 2 (1 + u2)2 u2∂uΦ++∂uΦ−−1. (9.7) We look o a change o a iables o he o m u= +X( , θ)such ha ∆ou ( , θ) = e ∆ou ( +X( , θ), θ) sa is ies L∆ou = 0, whe e L∆ = ∂u∆ + νI0∂θ∆was in oduced in (4.7). No ice ha , p o ided 7→ +X( , θ)is in e ible, e ∆ou sa is ies (9.6) i and only i ∆sa is ies 1 1 + ∂ X 1 + B 1 + A|(u,θ)=( +X( ,θ),θ)−νI0∂θX!∂ ∆ + νI0∂θ∆ = 0. Hence, we need o impose ha Xsa is ies LX=B−A 1 + A|(u,θ)=( +X( ,θ),θ) .(9.8) To sol e his equa ion, we conside he in e se Gou ,d o he ope a o Lde ined by he Fou ie coe icien s o he image Gou ,d(X): Gou ,d(X)[k](u) = Zu u+ 0 eikνI0(s−u)X[k](s)ds, k > 0, Gou ,d(X)[0](u) = Zu u0 X[0](s)ds, Gou ,d(X)[k](u) = Zu u− 0 eikνI0(s−u)X[k](s)ds, k < 0, (9.9) 48 whe e u+ 0,u− 0=u+ 0and u0∈Ra e opmos , bo ommos and eal le mos poin s in Dκ, espec- i ely. See Figu e 8. Rema k 9.1. The choice o he poin s u± 0and u0implies ha , i X(u, θ)is eal analy ic, so is Gou ,d(X). To sol e equa ion (9.8), o ∈R, we in oduce he Banach space o analy ic, 2π-pe iodic in θ unc ions Xs={X:Dκ×Tσ→C| kXks<∞}, wi h he no m kXks=X k∈ZkX[k]kse|k|σ, whe e, o an analy ic unc ion :Dκ→C, k ks= sup u∈Dκ|(1 + u2)s (u)|. Nex , we s a e wo echnical lemmas comple ely analogous o Lemmas 4.2 and 4.3. Lemma 9.2. Le s1, s2∈R. (1) I X∈ Xs1+s2and s2≥0, hen X∈ Xs1and he e exis s K > 0, independen o s1, s2such ha kXks1≤KνI0 κs2 kXks1+s2. (2) I X1∈ Xs1and X2∈ Xs2, hen X1X2∈ Xs1+s2and kX1X2ks1+s2≤ kX1ks1kX2ks2. Lemma 9.3. Le s∈Rand Gou ,d be he ope a o de ined by (9.9). (1) I X∈ Xswi h s≥0, hen Gou ,d(X)∈ Xsand kGou ,d(X)ks≤KkXks. I , u he mo e, hXi= 0, kGou ,d(X)ks≤K(νI0)−1kXks. (2) I X∈ Xswi h s > 1, hen Gou ,d(X)∈ Xs−1and kGou ,d(X)ks−1≤KkXks. (3) I X∈ Xswi h s > 0, hen ∂uGou ,d(X), ∂θGou ,d(X)∈ Xsand k∂uGou ,d(X)ks≤KkXks,k∂θGou ,d(X)ks≤K(νI0)−1kXks. Now, we summa ize he p ope ies o Aand Bwe need. Lemma 9.4. Le Aand Bbe he unc ions in oduced in (9.7). The e exis s K > 0such ha (1) A∈ X2wi h kAk2≤K(νI0)−2. (2) B=B1+B2whe e B1∈ X1,hB1i= 0,kB1k1≤K(νI0)−1and B2∈ X2wi h kB2k2≤ K(νI0)−2. Consequen ly, B∈ X1wi h kBk1≤K(νI0)−1. P oo . To p o e (1), we use he de ini ions in (9.1) and (9.7). F om P oposi ion 4.4 we ha e k∂θL+ ou k2≤K(νI0)−1and, om P oposi ion 4.5 and (1) o Lemma 9.2, k∂θΦ+ 2k2≤νI0 κ2 k∂θΦ+ 2k4≤νI0 κ2 (νI0)−1TΦ+ 2U3≤Kκ−2(νI0)−1. 49 Since he bounds o L− ou and Φ− 2a e he same as he ones o L+ ou and Φ+ 2, espec i ely, and ∂θΦ0= 0, we ha e kAk2=ν 2νI0∂θΦ++∂θΦ−2≤ν νI0k∂θL+ ou k2+k∂θΦ+ 2k2≤K(νI0)−2. Now we p o e (2). Using he de ini ion o Φ0in (4.5) we can check ha B=B1+B2, whe e B1(u, θ) = 1 2 (1 + u2)2 u2(∂uL+ ou (u, θ) + ∂uL− ou (u, θ)), B2(u, θ) = 1 2 (1 + u2)2 u2(∂uΦ+ 2(u, θ) + ∂uΦ− 2(u, θ)). By P oposi ion 4.4,k∂uL+ ou k3≤K(νI0)−1and since k(1+u2)2/u2k−2=O(1), by (2) o Lemma 9.2, kB1k1≤ 1 2 (1 + u2)2 u2−2k∂uL+ ou +∂uL− ou k3≤K(νI0)−1. Since hL+ ou i= 0 and (1 + u2)2/u2does no depend on θ,hB1i= 0. Finally, by P oposi ion 4.5,k∂uΦ+ 2k4≤TΦ+ 2U3≤K(νI0)−2. Then, kB2k2≤ 1 2 (1 + u2)2 u2−2k∂uΦ+ 2+∂uΦ− 2k4≤K(νI0)−2. Using he ope a o Gou ,d, we conside he ixed poin equa ion X=Gou ,d ◦Fou ,d(X),(9.10) whe e Fou ,d(X) = B−A 1 + A|(u,θ)=( +X( ,θ),θ) .(9.11) I is clea ha i Xsa is ies (9.10), hen Xis a solu ion o (9.8). Le X0=Gou ,d ◦Fou ,d(0). P oposi ion 9.5. X0∈ X1and kX0k1≤K(νI0)−2. Fu he mo e, X0is eal analy ic. P oo . We ha e ha Fou ,d(0) = B−A 1+A=B1+B2−A(B1+1) 1+A. By Lemma 9.4,kB1k1≤K(νI0)−1and hB1i= 0. Then, by (1) o Lemma 9.3,kGou ,d(B1)k1≤ K(νI0)−1kB1k1≤K(νI0)−2. Also, by Lemma 9.4,kB2k2≤K(νI0)−2. Then, he claim ollows om he bound  B2−A(B1+ 1) 1 + A2≤ kB2k2k(1 + A)−1k0+kAk2kB1+ 1k0k(1 + A)−1k0 and (2) o Lemma 9.3. The ollowing lemma is analogous o Lemma 8.3. The only di e ence is he geome y o he domain. Ac ually Dκdepends on κ, δ, β1and β2. Ha ing ixed some κ0,δ0,β1and β2wi h β2> β1 we will w i e b Dκ o deno e a amily o domains wi h κ > κ0and δ < δ0and wi h he same angles β1, β2such ha i ˜κ > κ > κ0 he dis ance om b D˜κ o he bounda y o b Dκis (˜κ−κ)(νI0)−1cos β1. This implies de e mining ˜ δ, depending on ˜κso ha (δ−˜ δ) cos β2= (˜κ−κ)(νI0)−1cos β1. No e ha a change in ˜κo o de one p oduces a change in ˜ δo o de (νI0)−1. Lemma 9.6. Le C∈ Xsin b Dκ×Tσand X∈ X in b D˜κ×Tσwi h s, ≥1and ˜κ > κ. We de ine CX( , θ) = C( +X( , θ), θ),( , θ)∈b D˜κ×Tσ. Then, he e exis s κ0such ha o any ˜κ > κ > κ0 he e exis K0, K1>0, depending on ˜κ, κ bu independen on νI0, such ha he ollowing holds. 50 (1) ∂j C∈ Xs+jin b D˜κ×Tσand k∂j Cks+j≤K1j!Kj 0kCks,j≥0. (2) I X∈ X in b D˜κ×Tσ, hen CX∈Xsin b D˜κ×Tσand kCXks≤ kCks K 1−K0(νI0˜κ−1) kXk . (3) I X, X′∈ X in b D˜κ×Tσ, wi h kXk ,kX′k ≤K, kCX−CX′ks+1 ≤K(νI0˜κ−1) kCkskX−X′k . P oo . (1) is an immedia e consequence o Cauchy es ima es in he educed domain. Using (1) o Lemma 9.2, (2) ollows om kCX( , θ)ks=X j≥0 1 j!∂j C( , θ)Xj( , θ)s ≤X j≥0 1 j!k∂j C( , θ)kskXkj 0 ≤X j≥0 K j!νI0 ˜κ j k∂j C( , θ)ks+jkXkj ≤KK1X j≥0 νI0 ˜κ K0kXk !j kCks =kCks KK1 1−νI0 ˜κ K0kXk . (3) ollows om C( +X( , θ), θ)−C( +X′( , θ), θ) =Z1 0 ∂ C( +X′( , θ) + s(X( , θ)−X′( , θ)), θ)ds (X−X′), (1) and (2) and he ac ha kXk0≤K(νI0/˜κ) kXk . To sol e equa ion (9.10), we in oduce e Xby se ing X=X0+e X. Then, Xis a solu ion o (9.10) i and only i e Xsa is ies e X=Gou ,d ◦e Fou ,d(e X),(9.12) whe e e Fou ,d(e X) = Fou ,d(X0+e X)−Fou ,d(0). P oposi ion 9.7. The e exis s κ0such ha , o any κ > κ0, equa ion (9.12)has a unique solu ion e X1∈ X1wi h ke X1k1≤K(νI0)−2/κ2. As a consequence, X=X0+e X1∈ X1is a solu ion o (9.10), kXk1≤K(νI0)−2and i is eal analy ic. P oo . We i s ema k ha , by Lemma 9.2 kAk0≤K(νI0)2kAk2/κ2,kAk1≤KνI0kAk2/κ, and aking in o accoun Lemma 9.4,(B−A)/(1 + A)∈ X1wi h k(B−A)/(1 + A)k1≤ kB−Ak1k(1 + A)−1k0≤K(νI0)−1. Since X0∈ X1in b Dκwi h kX0k1≤K(νI0)−2, by (3) o Lemma 9.6, aking X′= 0,s= 1, = 1 and ˜κ > κ we ha e ha e Fou ,d(0) ∈ X2in b D˜κwi h ke Fou ,d(0)k2≤KνI0 ˜κ B−A 1 + A1kX0k1≤Kκ−1(νI0)−2. Hence, by (2) o Lemma 9.3,kGou ,d ◦e Fou ,d(0)k1≤ kGou ,dkke Fou ,d(0)k2≤K(νI0)−2/˜κ, whe e he e kGou ,dkis he no m o he ope a o Gou ,d :X2→ X1. Le K∗= 2kGou ,d ◦e Fou ,d(0)k1. Wi h he same a gumen , i X, X′∈ X1wi h kXk1,kX′k1≤K∗, ke Fou ,d(X)−e Fou ,d(X′)k2≤KνI0 ˜κ B−A 1 + A1kX−X′k1≤K ˜κkX−X′k1in b D˜κ, 51 o some K > 0, independen o νI0and ˜κ. Finally, using again (2) o Lemma 9.3, kGou ,d ◦e Fou ,d(X)−Gou ,d ◦e Fou ,d(X′)k1 ≤ kGou ,dkke Fou ,d(X)−e Fou ,d(X′)k2≤kGou ,dkK ˜κkX−X′k1, which p o es ha Gou ,d ◦e Fou ,d is a con ac ion in b D˜κi ˜κis la ge enough. Now we can check ha Gou ,d ◦e Fou ,d sends BK∗⊂ X1in o i sel and he e o e Gou ,d ◦e Fou ,d has a unique ixed poin in ha ball. The eal analy ici y claim ollows om he de ini ions o Fou ,d and e Fou ,d and Rema k 9.1. P oposi ion 9.8. Le Xbe he unc ion, in he domain ˆ Dκ×Tσ, gi en by P oposi ion 9.7. Then, he map Θ( , θ) =  +X( , θ) θ is a well de ined change o a iables in ˆ Dκ×Tσ. I s in e se, Θ−1(u, θ) = u+Y(u, θ) θ=u−X(u, θ) + b X(u, θ) θ, is well de ined and eal analy ic in ˆ D˜κ×Tσ, o some ˜κ > κ, wi h Y∈ X1and kYk1≤K(νI0)−2. Mo eo e Y=−X+b Xwi h b X∈ X1and kb Xk1≤κ−1(νI0)−3in ˆ D˜κ×Tσ. P oo . The unc ion Yis he solu ion o he ixed poin equa ion Y=P(Y), whe e P(Y)(u, θ) = −X(u+Y(u, θ), θ). Clea ly, P(0) = −X∈ X1, wi h kP(0)k1=kXk1≤K(νI0)−2. We de ine K∗= 2K1kXk1. Then, by (2) o Lemma 9.6, i Y∈ BK∗⊂ X1,kP(Y)k1≤K(νI0)−2. Since, by P oposi- ion 9.7,X∈ X1, using (3) o Lemma 9.6,P es ic ed o BK∗is Lipschi z wi h Lipschi z cons an K˜κ−1νI0kXk1≤K˜κ−1(νI0)−1. Hence, i is a con ac ion i ˜κ−1(νI0)−1is small enough. Now, one easily checks ha P(BK∗)⊂ BK∗. Le Y0be he unique ixed poin o Pin BK∗. Then, w i ing Y0=−X+b X, kb Xk1=kY0+Xk1=kP(Y0)−P(0)k1≤K1 κνI0kY0k1≤K1 κ(νI0)3. 9.2 The exponen ially small o mula o Φ+−Φ− In his sec ion we inally ob ain he o mula o he di e ence e ∆ou = Φ+−Φ− o eal alues o uand θ. Fi s , we in oduce Υ+(u, θ) = νI0∆in(νI0(u+Y(u, θ)−i), θ), whe e he unc ion Yis gi en by P oposi ion 9.8.Υ+is de ined in {u∈C| ℑu < 1−κ(νI0)−1+ min{ an β1ℜu, − an β1ℜu}} which con ains he domain Dκ. We also de ine Υ−(u, θ) = Υ+(u, θ)(9.13) and Υ=Υ++ Υ−.(9.14) This de ini ion implies ha Υis eal analy ic. We ecall ha , since Lin∆in = 0 (see Theo em 8.6), we ha e ∆in( , θ) = X k≥1 keik(θ− ), 52 whe e he coe icien s kdo no depend on νI0. Then, in oducing Υk=νI0 ke−kνI0, k ≥1,(9.15) we ha e Υ+(u, θ) = X k≥1 Υkeik(θ−νI0u−νI0Y(u,θ)) and Υ−(u, θ) = X k≤−1 Υ−keik(θ−νI0u−νI0Y(u,θ)), since Yis eal analy ic. The unc ion Υwill be he desi ed i s o de o Φ+−Φ−. In o de o p o e his ac , we in oduce E(u, θ) = e ∆ou (u, θ)−Υ(u, θ) de ined in Dκ. P oposi ion 9.9. Le N∈Nbe ixed. The e exis s K > 0and s > 0such ha , o all (u, θ)∈ Dslog(νI0)×Tσsuch ha νI0(u−i)∈ D+ slog(νI0),α ∩−D+ slog(νI0),α,0≤j+k≤N, |∂j u∂k θE(u, θ)| ≤ K(νI0)j+1 max{(νI0)−2α,(νI0)−1+αlog(νI0),(νI0)−s} log(νI0), whe e he domain Dκwas in oduced in (9.3)and D+ κ,α in (7.4). P oo . Since Eis eal analy ic, i is enough o bound i o ℑu≥0. We w i e E=E1+E2+E3, whe e E1(u, θ) = Φ+(u, θ)−Φ−(u, θ)−νI0T+(νI0(u−i), θ)−T−(νI0(u−i), θ), he unc ion T+was gi en by Co olla y 6.6 and T−was in oduced in (8.1), E2(u, θ) = νI0T+(νI0(u−i), θ)−T−(νI0(u−i), θ)−Υ+(u, θ) and E3(u, θ) = −Υ−(u, θ). We bound each e m sepa a ely. We s a wi h E1. We claim ha |E1(u, θ)| ≤ KνI0 max{(νI0)−2α,(νI0)−1+αlog(νI0)} slog(νI0).(9.16) Indeed, o (u, θ)∈ Dslog(νI0)×Tσsuch ha νI0(u−i)∈ D+ slog(νI0),α ∩−D+ slog(νI0),α, by P oposi ion 7.5, |E1(u, θ)| ≤ 2νI0kS+ 2k0≤KνI0 slog(νI0)kS+ 2k1≤KνI0 max{(νI0)−2α,(νI0)−1+αlog(νI0)} slog(νI0). To bound E2we obse e ha , by Theo em 8.6 and P oposi ions 9.5 and 9.8, E2(u, θ) = νI0∆in(νI0(u−i) + Z(νI0(u−i), θ), θ)−∆in(νI0(u−i+Y(u, θ)), θ). Also, aking in o accoun ha kZk1≤Kand kYk1=K(νI0)−2, we ha e ha |Z(νI0(u−i), θ)| ≤ K νI0|u−i|, |νI0Y(u, θ)| ≤ K νI0|u−i|. 53 Hence, by he mean alue heo em, o (u, θ)∈ Dslog(νI0)×Tσwe ha e ha |E2(u, θ)| ≤ KνI0 s(νI0)slog(νI0)4. Finally, o bound E3we i s obse e ha , o (u, θ)∈ Dslog(νI0)×Tσwi h ℑu≥0, since Yis eal analy ic, which implies ha ℑY(ℜu, ℜθ) = 0, and kYk1=O((νI0)−2), ℑ(u+Y(u, θ)) ≥(1 −k∂uYk0)ℑu≥(1 −K(νI0)2/(slog(νI0))2kYk1)ℑu ≥(1 −K/(slog(νI0))2)ℑu≥0, whe e we ha e used Cauchy es ima es o ela e ∂uYand Y, and we ha e sligh ly educed he domain by conside ing a bigge alue o s. Hence, om he de ini ion o Υ−in (9.13) and (9.15), o (u, θ)∈ Dslog(νI0)×Tσwi h ℑu > 0, |E3(u, θ)| ≤ X k≤−1 νI0| −k|ek(νI0−σ)ek(νI0ℑu(1+O((νI0)−1))) ≤X k≤−1 νI0| −k|ek(νI0−σ)≤KνI0e−(νI0−σ). The bounds o he s a emen ollow applying s anda d Cauchy es ima es and sligh ly educing he domain. Finally, we need he ollowing elemen a y lemma. Lemma 9.10. Le Ψ : Dslog(νI0)×Tσ→Cbe an analy ic unc ion. We w i e Ψ(u, θ) = Pk∈ZΨ[k](u)eikθ. Assume (i) LΨ=0. (ii) The e exis s M > 0such ha |Ψ[k](±(i−is log(νI0)/(νI0)))| ≤ M. Then, Ψ(u, θ) = Pk∈ZΛkeik(θ−νI0u)and |Λ±k| ≤ M(νI0)kse−kνI0, k ≥1. P oo . Since LΨ = 0, he e exis s a 2π-pe iodic unc ion Λ(φ) = Pk∈ZΛkeikφ such ha Ψ(u, θ) = Λ(θ−νI0u). Since Ψis also pe iodic wi h espec o θ, we ha e ha Ψ(u, θ) = Pk∈ZΨ[k](u)eikθ, ha is Ψ[k](u) = Λke−ikνI0u. The claim ollows e alua ing he abo e equali y a u=i−is log(νI0)/(νI0), o k≥1, and a u=−i+is log(νI0)/(νI0), o k≤ −1. Theo em 9.11. Fix αsuch ha min{2α, 1−α}>0. Take 0< s < min{2α, 1−α}and ix N∈Nas in P oposi ion 9.9. The e exis s Λ0∈Rsuch ha , o all (u, θ)∈(Dslog(νI0)∩R)×Tσ, 0≤j+k≤N. Le ∂j u∂k θ(e ∆ou (u, θ)−Λ0) = ∂j u∂k θΥ(u+Y(u, θ), θ) + OνI0e−νI0 log(νI0) =νI0e−νI02 1∂j u∂k θ(cos(θ−νI0u)) + O1 log(νI0), whe e 1is gi en in Theo em 8.6. Fu he mo e, i one eplaces he iin he de ini ion o he coe icien s io Vin (1.2)by ε i, we ha e ha 1=επ 1 4+O(ε2).(9.17) 54 P oo . By P oposi ion 9.7 and Theo em 8.6, we ha e ha e E(u, θ) = e ∆ou (u+X(u, θ), θ)−Υ(u+X(u, θ), θ) sa is ies Le E= 0. Since kXk1≤K(νI0)−2,e Esa is ies he same bounds as Egi en by P oposi ion 9.9. W i ing e E(u, θ) = Pk∈Ze Ekeik(θ−νI0u), by Lemma 9.10 we ha e ha |e E±1| ≤ KνI0 log(νI0)e−νI0, |e E±k| ≤ KνI0 log(νI0)e−kνI0(1−slog(νI0))/(νI0), k ≥2. Hence, o (u, θ)∈(Dslog(νI0)∩R)×Tσ, |e E(u, θ)−e E0| ≤ KνI0 log(νI0)e−νI0.(9.18) Since kYk1≤K(νI0)−2, we ha e ha |Y(u, θ)| ≤ K(νI0)−2 o u∈R. Then, om he de ini ion o Υin (9.14) and using ha 1∈R, we ha e ha , o (u, θ)∈(Dslog(νI0)∩R)×Tσ, Υ(u, θ) = νI0 X k≥1 ke−kνI0eik(θ−νI0(u+Y(u,θ))) +X k≤−1 −kekνI0eik(θ−νI0(u+Y(u,θ)))  =νI0e−νI02 1cos(θ−νI0u) + O((νI0)−1). Hence, using again kYk1≤K(νI0)−2,Ealso sa is ies (9.18), o (u, θ)∈(Dslog(νI0)∩R)×Tσ, and, om e ∆ou = Υ + E, e ∆ou (u, θ)−Λ0=νI0e−νI02 1cos(θ−νI0u) + O((log(νI0))−1), whe e Λ0=e E0. The las claim ollows immedia ely om (9.15) and Theo em 8.6. 10 Acknowledgemen s F. B has been pa ially suppo ed by he g an PID2021-122711NB-C’21, E.F. has been pa ially suppo ed by he g an PID2021-125535NB-I00, and P.M. has been pa ially suppo ed by he g an PID2021-123968NB-I00, unded by he Spanish S a e Resea ch Agency h ough he p og ams MCIN/AEI/10.13039/501100011033 and “ERDF A way o making Eu ope”. Also, E.F. and P.M. au ho s ha e been pa ially suppo ed by he Spanish S a e Resea ch Agency, h ough he Se e o Ochoa and Ma ía de Maez u P og am o Cen e s and Uni s o Excel- lence in R&D (CEX2020-001084-M). A P oo o Theo em 3.2 We i s in oduce a new ime in sys em (3.3) so ha he o igin becomes a ue saddle. Since he solu ions o (3.3) wi h ini ial condi ion (u0, 0, 0)∈Vρwi h u0, 0≥0and u0+ 0>0sa is y u( ) + ( )≥0while hey belong o Vρ, we de ine he new ime ssuch ha d /ds = (u+ )−1. Equa ion (3.3) becomes u′=u(1 + O1(u, )), ′=− (1 + O1(u, )), ′= (u+ )−1, (A.1) whe e ′deno es d/ds. The O1(u, ) e ms depend on sand a e uni o mly bounded in e ms o (u, )in Vρ. Gi en w0= (u0, 0, 0)∈Vρ, we de ine sw0= sup {s > 0|w(˜s)∈Vρ,∀˜s∈[0, s)},(A.2) whe e wis he solu ion o (A.1) wi h ini ial condi ion w0. Nex lemma implies (1) o Theo em 3.2. I s p oo is pos poned o Appendix B. 55 Lemma A.1. The e exis ρ∈(0,1) and C > 0, sa is ying Cρ < 7/8, such ha he solu ion w= (u, , )o (3.3)wi h ini ial condi ion w0= (u0, 0, 0)∈Vρwi h u0, 0>0sa is ies log ρ u01 1+Cρ !≤sw0≤log ρ u01 1−Cρ !. Mo eo e , o any 0< a ≤ρand 0< δ < a/2, he “Poinca é map" Ψ : Σ1 a,δ →Σ0 a,δ1−Ca , whe e he se s Σ0 a,δ and Σ1 a,δ a e de ined in (3.4), is well de ined and, i w= (u0, a, 0)∈Σ1 a,δ and Ψ(w) = (a, 1, 1), hen u1+Ca 0≤ 1≤u1−Ca 0, e C1u−(1−Ca)/2 0≤ 1− 0≤e C2u−(1+Ca)/2 0 o some cons an s e C1,e C2>0depending only on ρ. Le w= (u, , )be a solu ion o (3.3) wi h ini ial condi ion w0∈Vρ. We in oduce τ= /u (A.3) and we will w i e Oi=Oi(u, ). We ha e ha 0< τ(s)<∞, o all ssuch ha w∈Vρ. I is immedia e om (A.1) ha dτ ds =−(2 + O1)τ. (A.4) The a ia ional equa ions a ound a solu ion o sys em (3.3) a e   ˙ U ˙ V ˙ T = 2u+ +O2u(1 + O1)uO2 − (1 + O1)−u−2 +O2 O2 0 0 0   U V T .(A.5) To p o e (2) o Theo em 3.2, we will s udy he beha io o he solu ions o (A.5) wi h ini ial condi ion U=U06= 0 along solu ions o (3.3) wi h ini ial condi ion w0= (u0, 0, 0)∈Vρ∩{u, > 0} o 0=asmall bu ixed and u0a bi a ily small. Equa ions (A.5) become, in he ime sin which he equa ions in (A.1) a e w i en, and using τin (A.3),  U′ V′ T′ =  2+τ+O1 1+τ 1+O1 1+τuO1 −(1+O1)τ 1+τ−1+2τ+O1 1+τ O1 0 0 0   U V T .(A.6) P oposi ion A.2. The e exis s α∗, wi h 0< α∗<5/12 such ha o any ρ > 0small enough, any w= (u, , ), solu ion o (A.1)wi h w|s=0 =w0= (u0, 0, 0)∈Vρand any α∗ 0∈[0, α∗], he e exis s α: [0, sw0]→R,C∞, whe e sw0was de ined in (A.2), wi h α(0) = α∗ 0, such ha , in oducing he new a iable e V=V+αU, equa ion (A.6)becomes   U′ e V′ T′ =  2+τ+O1 1+τ−α1+O1 1+τ 1+O1 1+τuO1 0−1+2τ+O1 1+τ+α1+O1 1+τ O1 0 0 0    U e V T .(A.7) Fu he mo e, o s∈(0, sw0], 0< α(s)<55 128 τ(s) 1 + τ(s).(A.8) 56 P oo . Gi en αand e V=V+αU, since τ > 0, he equa ion o e Vis e V′=−(1 + O1)τ 1 + τ+α′+ (3 + O1)α−α21 + O1 1 + τU(A.9) +−1 + 2τ+O1 1 + τ+α1 + O1 1 + τe V+ ( +αu)TO1.(A.10) The claim will ollow inding an app op ia e solu ion o α′=ν0+ν1α+ν2α2,(A.11) whe e ν0=(1 + O1)τ 1 + τ, ν1(s) = −3 + O1, ν2=1 + O1 1 + τ. Le (w, α) = ν0+ν1α+ν2α2be he igh hand side o (A.11), whe e we ha e omi ed he dependence o νi,i= 1,2,3, on wand s. We in oduce α0and α1, he nullclines o (A.11), by (w, α) = ν2(α−α0(τ))(α−α1(τ)), and R, whe e α0(τ) = −ν1 2ν2 1−1−4ν0ν2 ν2 11/2! =3 2+O1 1 + τ−(1 + τ)2−4 9+O1τ1/2! =3 2+O11 + τ−pR(τ). To comple e he p oo o P oposi ion A.2, we need he ollowing wo auxilia y lemmas. Lemma A.3. The unc ion α0has he ollowing p ope ies. Fo (u, )∈Va( ha is, 0< τ < ∞), (1) 2√2/3 + O1≤pR(τ)/(1 + τ)<1, (2) limτ→∞ α0(τ) = 1/3 + O1, (3) limτ→0α0(τ)/τ = 1/3 + O1, (4) d dsα0=−(1 + O1)√R−τ+ 1 + O1 √Rα0, (5) −(2 + O1) √Rα0≤d dsα0≤ −(16/9 + O1) √Rα0 (6) limτ→0(dα0/ds)/α0=−2 + O1. Fu he mo e, 0< α0(τ)<11 32 τ 1 + τ.(A.12) P oo . I ems (1) o (6) a e p o en in [GK12]. The bound (A.12) ollows om a di ec compu a ion. Nex lemma p o ides solu ions o (A.11) close o he nullcline α0. The p oo s o he nex wo lemmas a e gi en in Appendix B. Lemma A.4. Fo any 0< ρ < 1small enough, he ollowing is ue. Fo any solu ion w= (u, , ) o (3.3)wi h ini ial condi ion w0∈Vρ×T, i αis a solu ion o (A.11)wi h 0≤α(s0)≤ 5α0(τ(s0))/4 o some 0< s0< sw0, hen 0< α(s)<5α0(τ(s))/4 o all s∈[s0, sw0]. 57